\(=\dfrac{1}{5}\left(\dfrac{5}{4\cdot9}+\dfrac{5}{9\cdot14}+...+\dfrac{5}{44\cdot49}\right)\cdot\dfrac{-7}{1}\)
\(=\dfrac{-7}{5}\left(\dfrac{1}{4}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{14}+...+\dfrac{1}{44}-\dfrac{1}{49}\right)\)
\(=\dfrac{-7}{5}\cdot\dfrac{45}{196}=-\dfrac{9}{28}\)