Question

Answer 1

giúp mềnh ới

Answer 2

\(\Leftrightarrow\dfrac{-7}{x-3}=\dfrac{x-3}{-7}\)

\(\Leftrightarrow\left(x-3\right)^2=49\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=7\\x-3=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-4\end{matrix}\right.\)

Answer 3

`(-7)/(x-3) = (3-x)/7`

`<=> (-7)/x-3)=(x-3)/-7`

`=> `(x-3)(x-3)=(-7).(-7)`

`=>` \(\left[{}\begin{matrix}\left(x-3\right)^2=-7^2\\\left(x-3\right)^2=7^2\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x-3=-7\\x-3=7\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=-7+3\\x=7+3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=-4\\x=10\end{matrix}\right.\)