Question

Answer 1

Câu 1: 

a: \(=\dfrac{2x\left(x+1\right)}{3\left(x+1\right)}=\dfrac{2x}{3}\)

b: \(=\dfrac{\left(x+2\right)\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}=\dfrac{x+2}{x+1}\)

c: \(=\dfrac{x\left(x+4\right)}{x\left(x-6\right)}=\dfrac{x+4}{x-6}\)

d: \(=\dfrac{\left(x+2\right)^2}{x\left(x+2\right)}=\dfrac{x+2}{x}\)

e: \(=\dfrac{x\left(x+2\right)}{\left(x+2\right)\left(2-x\right)}=\dfrac{x}{2-x}\)

f: \(=\dfrac{x\left(x-2\right)\left(x+2\right)}{x+2}=x^2-2x\)

h: \(=\dfrac{x\left(x+2\right)}{2\left(x+2\right)}=\dfrac{x}{2}\)

i: \(=\dfrac{\left(x-2\right)\left(x-4\right)}{x-2}=x-4\)

Answer 2

2
a)\(\dfrac{x^3+8}{x^2-2x+4}=\dfrac{x^3+2^3}{x^2-2x+4}=\dfrac{\left(x+2\right)\left(x^2-2x+4\right)}{x^2-2x+4}=x^2\)
b)\(\dfrac{x^2+2x+4}{x^3-8}=\dfrac{x^2+2x+4}{\left(x-2\right)\left(x^2+2x+4\right)}=\dfrac{1}{x-2}\) 
c)\(\dfrac{x^3-6x^2+12x-8}{x-2}=\dfrac{\left(x-2\right)^3}{x-2}=\left(x-2\right)^2\)