Câu 1:
a) Ta có: 5x-4=2x+11
\(\Leftrightarrow5x-2x=11+4\)
\(\Leftrightarrow3x=15\)
hay x=5
Vậy: S={5}
b) Ta có: x(3x-5)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\3x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\3x=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{5}{3}\end{matrix}\right.\)
Vậy: \(S=\left\{0;\dfrac{5}{3}\right\}\)
Câu 1:
c) Ta có: 2x+3=0
\(\Leftrightarrow2x=-3\)
hay \(x=-\dfrac{3}{2}\)
Vậy: \(S=\left\{-\dfrac{3}{2}\right\}\)
d) Ta có: 5x-4=2x+1
\(\Leftrightarrow5x-2x=1+4\)
\(\Leftrightarrow3x=5\)
hay \(x=\dfrac{5}{3}\)
Vậy: \(S=\left\{\dfrac{5}{3}\right\}\)
