Question

Answer 1

nFe=m/M=112/56=2mol

Answer 2

\(\text{V}_{\text{C}\text{O}\text{2}}=0,25.44=11\left(l\right)\)

\(\text{V}_{\text{N}\text{2}}=0,5.14=7\left(l\right)\)

Answer 3

số mol của Cl2 là

nCl2=\(\dfrac{\text{0},71}{\text{71}}=0,01\)mol

số mol của H2 là 

nH2=\(\dfrac{\text{0},04}{\text{2}}\)=\(0,02\)mol

Answer 4

\(a,n_{Fe}=\dfrac{m}{M}=\dfrac{112}{56}=2\left(mol\right)\\ b,V_{CO_2\left(dktc\right)}=n.22,4=0,25.22,4=5,6\left(l\right)\\ V_{N_2\left(dktc\right)}=n.22,4=0,5.22,4=11,2\left(l\right)\\ c,n_{Cl_2}=\dfrac{m}{M}=\dfrac{0,71}{71}=0,01\left(mol\right)\\ n_{hh}=n_{Cl_2}+n_{H_2}=0,01+0,04=0,05\left(mol\right)\)