\(a,PTHH:CuO+H_2\xrightarrow{t^o}Cu+H_2O\\ b,n_{Cu}=\dfrac{6,4}{64}=0,1(mol)\\ \text{Theo PT: }n_{H_2}=n_{Cu}=0,1(mol)\\ \Rightarrow V_{H_2}=0,1.22,4=2,24(l)\\ c,n_{CuO}=\dfrac{40}{80}=0,5(mol)\\ \text{Theo PT: }n_{Cu}=n_{CuO}=0,5(mol)\\ \Rightarrow m_{Cu}=64.0,5=32(g)\)
\(a,PTHH:H_2+CuO\underrightarrow{t^o}Cu+H_2O\)
\(b,n_{Cu}=\dfrac{m}{M}=\dfrac{6,4}{64}=0,1\left(mol\right)\\ Theo.PTHH\Rightarrow n_{H_2}=n_{CuO}=n_{Cu}=n_{H_2O}=0,1\left(mol\right)\)
\(\Rightarrow V_{H_2\left(đktc\right)}=n.22,4=0,1.22,4=2,24\left(l\right)\)
\(c,n_{CuO}=\dfrac{m}{M}=\dfrac{40}{80}=0,5\left(mol\right)\\ Theo.PTHH\Rightarrow n_{H_2}=n_{CuO}=n_{Cu}=n_{H_2O}=0,5\left(mol\right)\\ \Rightarrow m_{Cu}=n.M=0,5.64=32\left(g\right)\)
a: \(H_2+CuO\rightarrow Cu+H_2O\)
b: \(n_{Cu}=\dfrac{6.4}{64}=0.1\left(mol\right)\)
\(\Leftrightarrow n_{Cu}=n_{CuO}=n_{H_2O}=n_{H_2}=0.1\left(mol\right)\)
\(V=n\cdot22.4=0.1\cdot22.4=2.24\left(lít\right)\)
