Question

Answer 1

giúp mình với

 

Answer 2

a) \(\dfrac{x-1}{3.5}=\dfrac{2}{7}\)

<=> \(x-1=\dfrac{2.15}{7}\)

<=> x=\(\dfrac{37}{7}\)

b)\(\left(\dfrac{2}{3}-x\right)^3=-\sqrt{\dfrac{1}{64}}\)

<=> \(\left(\dfrac{2}{3}-x\right)^3=\dfrac{-1}{8}\)

<=> \(\dfrac{2}{3}-x=\dfrac{-1}{2}\)

<=> x=\(\dfrac{7}{6}\)