Bài 6:
\(\frac{12}{-6}=\frac{x}{5}=\frac{-y}{3}=\frac{z}{-17}=\frac{-t}{-9}\)
=>\(\frac{x}{5}=\frac{y}{-3}=\frac{z}{-17}=\frac{t}{9}=-2\)
=>\(x=-2\cdot5=-10;y=\left(-2\right)\cdot\left(-3\right)=6;z=\left(-2\right)\cdot\left(-17\right)=34;t=-2\cdot9=-18\)
Bài 7:
\(\frac{-24}{6}=\frac{x}{3}=\frac{4}{y^2}=\frac{z^3}{-2}\)
=>\(\frac{x}{3}=\frac{4}{y^2}=\frac{z^3}{-2}=-4\)
=>\(\begin{cases}x=-4\cdot3=-12\\ y^2=\frac{4}{-4}=-1\left(loại\right)\\ z^3=8\end{cases}\)
=>(x;y;z)∈∅

