Question

Answer 1

\(ĐK:\dfrac{3}{2}\le x\le3\\ PT\Leftrightarrow3-x=4x^2-12x+9\\ \Leftrightarrow4x^2-11x+6=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\left(tm\right)\\x=\dfrac{3}{4}\left(ktm\right)\end{matrix}\right.\)

Answer 2

ĐKXĐ: \(\dfrac{3}{2}\le x\le3\)

\(pt\Leftrightarrow3-x=4x^2-12x+9\)

\(\Leftrightarrow4x^2-11x+6=0\)

\(\Leftrightarrow4x\left(x-2\right)-3\left(x-2\right)=0\Leftrightarrow\left(x-2\right)\left(4x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\left(tm\right)\\x=\dfrac{3}{4}\left(ktm\right)\end{matrix}\right.\)