Question

Answer 1

\(B=\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{3}}-\dfrac{2\left(\sqrt{3}+1\right)}{3-1}=\sqrt{3}+1-\sqrt{3}-1=0\)

Answer 2

\(=\sqrt{3}+1-\sqrt{3}-1=0\)

Answer 3

b) \(B=\dfrac{3+\sqrt{3}}{\sqrt{3}}-\dfrac{2}{\sqrt{3}-1}\\ =\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{3}}-\dfrac{2\left(\sqrt{3}+1\right)}{\left(\sqrt{3}\right)^2-1^2}\\ =\sqrt{3}+1-\sqrt{3}-1\\ =0\)