Question

Answer 1

Bài 1: 

a: \(\sqrt{75a^3}=5a\sqrt{3a}\)

b: \(\sqrt{98a^5\left(b^2-6b+9\right)}=7a^2\cdot\left|b-3\right|\cdot\sqrt{2a}\)

Answer 2

\(2,\\ a,=10\sqrt{5}-15\sqrt{5}+12\sqrt{5}=7\sqrt{5}\\ b,=10\sqrt{3}-12\sqrt{3}+2\sqrt{3}=0\\ 3,\\ a,\left(3\sqrt{7}\right)^2=63>60=\left(2\sqrt{15}\right)^2\\ \Leftrightarrow3\sqrt{7}>2\sqrt{15}\\ b,\left(4\sqrt{5}\right)^2=40< 75=\left(5\sqrt{3}\right)^2\\ \Leftrightarrow4\sqrt{5}< 5\sqrt{3}\Leftrightarrow-4\sqrt{5}>-5\sqrt{3}\)