Question

Answer 1

\(\sqrt{\dfrac{4x+3}{x+1}}=3\)

\(\Leftrightarrow4x+3=9x+9\)

\(\Leftrightarrow-5x=6\)

hay \(x=-\dfrac{6}{5}\)

Answer 2

\(\sqrt{\dfrac{4x+3}{x+1}}\)=3

hay 

Answer 3

ĐKXĐ:x\(\ge\dfrac{-3}{4}\)

\(\sqrt{\dfrac{4x+3}{x+1}}=3\\ \Leftrightarrow\dfrac{4x+3}{x+1}=9\\ \Leftrightarrow4x+3=9x+9\\ \Leftrightarrow5x+6=0\\ \Leftrightarrow x=\dfrac{-6}{5}\)

Vậy x = -6/5.