Question

Answer 1

Vì \(\dfrac{13}{n-3}\in Z\)

=> 13 chia hết cho n - 3

=> \(n-3\inƯ\left(13\right)\)

=> \(n-3\in\left\{-13;-1;1;13\right\}\)

=> \(n\in\left\{-10;2;4;16\right\}\)

Answer 2

Để \(\dfrac{13}{n-3}\) là số nguyên thì \(n-3\in\left\{1;-1;13;-13\right\}\)

hay \(n\in\left\{4;2;16;-10\right\}\)