Sai kìa

nhưng cũng đc rồi

nice

Giỏi quá

Giỏi quá

\(\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{4}{8}-\dfrac{1}{8}=\dfrac{4-1}{8}=\dfrac{3}{8}\)

Ghê ghê

PT: Zn + 2HCl ---> ZnCl₂ + H₂

n_Zn = \(\dfrac{6,5}{65}=0,1\left(mol\right)\)

a. Theo PT: \(n_{H_2}=n_{Zn}=0,1\left(mol\right)\)

=> \(V_{H_2}=0,1.22,4=2,24\left(lít\right)\)

\(\dfrac{3}{8}:\dfrac{2}{4}=\dfrac{3}{8}.2=\dfrac{6}{8}=\dfrac{3}{4}\)

Ta có x là Ư₍₇₂₎

Ư₍₇₂₎ là: \(\left\{1;2;3;4;6;8;9;12;18;24;36;72\right\}\)

mà 17 < x \(\le\) 36

=> \(x\in\left\{18;24;36\right\}\)