HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
16. C
17. B
18. B
19. A
20. C
21. A
22. C
23. D
24. D
26. A
27. C
28. A
29. B
30. C
31. C
32. C
33. C
34. C
35. D
36. D
15. D
16. D
18. C
20. A
21. C
22. D
23. A
24. A
25. D
27. D
28. C
29. D
30. B
31. A
6. B
7. D
8. B
9. B
10. B
11. A
12. D
13. A
14. C
1. He said if he had a permit, he could get a job.
2. He said if she had loved Tom, she wouldn’t have left him.
3. He asked me what I would do if I had time.
4. She said if I wanted to lose weight, I had to eat less bread.
5. He said if he had a map, he would lend it to me.
1. How often does your father go to work?
2. What are they doing at the moment?
a) M = \(\dfrac{\sqrt{x}}{\sqrt{x}-2}-\dfrac{4\sqrt{x}-4}{\sqrt{x}\left(\sqrt{x}-2\right)}\) = \(\dfrac{x-4\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-2\right)}\) = \(\dfrac{\left(\sqrt{x}-2\right)^2}{\sqrt{x}\left(\sqrt{x}-2\right)}=\dfrac{\sqrt{x}-2}{\sqrt{x}}\)
b) Ta có: x = 3 + 2\(\sqrt{2}\) = (\(\sqrt{2}\) + 1)2 => \(\sqrt{x}\) = \(\sqrt{2}\) + 1
=> M = \(\dfrac{\sqrt{2}+1-2}{\sqrt{2}+1}=\dfrac{\sqrt{2}-1}{\sqrt{2}+1}=3-2\sqrt{2}\)
c) M = \(\dfrac{\sqrt{x}-2}{\sqrt{x}}\)
Ta có: \(\sqrt{x}\) > 0 ∀x > 0 => Để M > 0 thì \(\sqrt{x}\) - 2 > 0 ⇔ \(\sqrt{x}\) > 2 ⇔ x > 4