200 - 100 =100

\(=2x+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{9}-\frac{1}{11}=-\frac{2016}{2017}\)

\(=2x+\frac{1}{3}-\frac{1}{11}=-\frac{2016}{2017}\)

\(2x+\frac{8}{33}=-\frac{2016}{2017}\)

\(2x=\frac{-2016}{2017}-\frac{8}{33}\)

\(2x=\frac{-2024}{2017}\)

\(x=-\frac{1012}{2017}\)

-x^2-8x+5

<=>-x(x+8)+5 

Ta thấy:\(-x\left(x+8\right)\le0\) với mọi x

\(\Rightarrow-x\left(x+8\right)+5\le0+5\)

\(\Rightarrow P\le5\)

Dấu "=" xảy ra khi x=0 hoặc 8

Vậy MaxP=5 <=>x=0 hoặc 8