Ta có
\(n_X=\frac{3,36}{22,4}=0,15\left(mol\right)\)
\(n_{CaCO_3}=\frac{10}{100}=0,1\left(mol\right)\)
\(n_{Cu}=\frac{4,8}{64}=0,075\left(mol\right)\)
PTHH
\(CuO+CO\rightarrow Cu+CO_2\uparrow\) (1)
\(Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\) (2)
Theo (2) \(n_{CO_2}=n_{CaCO_3}=0,1\left(mol\right)\Rightarrow n_{N_2}=0,15-0,1=0,05\left(mol\right)\)
\(\Rightarrow V_{N_2}=22,4\times0,05=1,12\left(l\right)\Rightarrow\%V_{N_2}=\frac{1,12}{3,36}\times100\approx33,33\%\)