\(3-\left(2\frac{2}{3}-x+\frac{5}{4}\right)=1-1\frac{1}{6}-\frac{5}{12}\)

\(3-\left(\frac{8}{3}+\frac{5}{4}-x\right)=1-\frac{7}{6}-\frac{5}{12}\)

\(3-\left(\frac{8.4+3.5}{12}-x\right)=\frac{12}{12}-\frac{14}{12}-\frac{5}{12}\)

\(3-\left(\frac{32+15}{12}-x\right)=-\frac{7}{12}\)

\(\frac{47}{12}-x=3-\left(-\frac{7}{12}\right)\)

\(\frac{47}{12}-x=3+\frac{7}{12}\)

\(\frac{47}{12}-x=\frac{36}{12}+\frac{7}{12}=\frac{43}{12}\)

\(x=\frac{47}{12}-\frac{43}{12}=\frac{4}{12}=\frac{1}{3}\)

224*12=2688