\(8sin^3\left(x+\frac{\Pi}{6}\right)=cos3x\)

\(\frac{3^x}{1+2^x}+\frac{4^x}{1+3^x}=2\)

sin3x - cos3x +2sin2x +1 =0

\(2^x+2^{\left(2^x\right)}=3-x+2^{3-x}\)

cos3x=cosx+sinx

12 sin⁴x + sin²2x+cos4x=1

\(tan\left(\frac{\Pi}{3}-3x\right)+tan2x+tanx=\sqrt{3}\)

\(4sin^2\left(x+\frac{\Pi}{6}\right)+sin2x=1\)

tan²x+cot²x+2cot2x=2