dễ ợt

rảnh thì rảnh nhg k biết bn còn onl k

\(\left|2x-1\right|-\dfrac{1}{2}=\dfrac{1}{3}\)

\(\Rightarrow\left|2x-1\right|=\dfrac{1}{3}+\dfrac{1}{2}=\dfrac{5}{6}\)

\(\Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{5}{6}\\2x-1=-\dfrac{5}{6}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{11}{6}\\2x=\dfrac{1}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{12}\\x=\dfrac{1}{12}\end{matrix}\right.\)

Vậy.....