2Al + 6HCl → 2AlCl3 + 3H2
\(n_{H_2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)
Theo PT: \(n_{Al}=\dfrac{2}{3}n_{H_2}=\dfrac{2}{3}\times0,3=0,2\left(mol\right)\)
\(\Rightarrow m_{Al}=0,2\times27=5,4\left(g\right)\)
Theo PT: \(n_{HCl}=2n_{H_2}=2\times0,3=0,6\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,6\times36,5=21,9\left(g\right)\)
Theo PT: \(n_{AlCl_3}=\dfrac{2}{3}n_{H_2}=\dfrac{2}{3}\times0,3=0,2\left(mol\right)\)
\(\Rightarrow m_{AlCl_3}=0,2\times133,5=26,7\left(g\right)\)