1.in

2.to

3.on

4.to

5.on

6.of

7.on

8.for

Bài vi

1.more interesting than

2.the most intelligent

3.the shortest

4.bigger than

5.the most comfortable

6.badly

7.more peaceful than

8.the cleverest

9.the most delicious

10.the most boring

11.is worse than

: D: 1994*867+1995*133=39890000

{a;2} ; {a;4} ; {b;2} ; {b;4} ; {c;2} ; {c;4} ; {d;2} ; {d;4}

(6;143)

(25;143)

(25;21)

(21;143)

(25;6)

A

will switch

Alexander Graham Bell was the inventor of telephone

\(\dfrac{x+1}{2014}+\dfrac{x+2}{2013}+.....+\dfrac{x+1007}{1008}=\dfrac{x+1008}{1007}+\dfrac{x+1009}{1006}+........+\dfrac{x+2014}{1}\)\(\Leftrightarrow\left(\dfrac{x+1}{2014}+1\right)+\left(\dfrac{x+2}{2013}+1\right)+...+\left(\dfrac{x+1007}{1008}+1\right)=\left(\dfrac{x+1008}{1007}+1\right)+\left(\dfrac{x+1009}{1006}+1\right)+...+\left(\dfrac{x+2014}{1}+1\right)\)\(\Leftrightarrow\dfrac{x+2015}{2014}+\dfrac{x+2015}{2013}+...+\dfrac{x+1007}{1008}=\dfrac{x+2015}{1007}+\dfrac{x+1009}{1006}+...+\dfrac{x+2014}{1}\)\(\Leftrightarrow\dfrac{x+2015}{2014}+\dfrac{x+2015}{2013}+...+\dfrac{x+2015}{1008}-\dfrac{x+1008}{1007}-\dfrac{x+2015}{1006}-...-\dfrac{x+2015}{1}=0\)\(\Leftrightarrow\left(x+2015\right)\left(\dfrac{1}{2014}+\dfrac{1}{2013}+...+\dfrac{1}{1008}-\dfrac{1}{1007}-\dfrac{1}{1006}-...-1\right)=0\)\(\Leftrightarrow x+2015=0\left(\dfrac{1}{2014}+\dfrac{1}{2013}+...+\dfrac{1}{1008}-\dfrac{1}{1007}-\dfrac{1}{1006}-...-1>0\right)\)\(\Leftrightarrow x=-2015\)

Vậy x=-2015

a ) theo đề ra . ta có :

28 chia hết cho a

36 chia hết cho a 

a > 2

b ) Theo đề ra , ta có :

a \(\in\)ƯC(28;36)

28 = 2².7

36 = 2².3²

2 = 2¹

UWCLN( 28 ; 36 ) = 2²=4

ƯC( 28 ; 36 ) = Ư(4)={1;2;4}

Mà số bút trong hộp lớn hơn 2 nên:

a=4

c ) Theo câu b , ta có :

Số bút chì màu trong hộp là 4 .

Vậy số hộp màu Mai mua là :

28 : 4 = 7 ( hộp )

Số Hộp màu Lan mua là :

36 : 4 = 9 ( hộp )