ln bản chất là log cơ số e rồi bạn. sao câu a lại có cơ số 2.

a) \(\log_2\left(mn\right)=\log_2\left(2^7.2^3\right)=\log_22^{7+3}=\log_22^{10}=10.\log_22=10.1=10\)

\(\log_2m+\log_2n=\log_22^7+\log_22^3=7\log_22+3\log_22=7.1+3.1=7+3=10\)

b) \(\log_2\left(\dfrac{m}{n}\right)=\log_2\dfrac{2^7}{2^3}=\log_22^4=4.\log_22=4.1=4\)

\(\log_2m-\log_2n=\log_22^7-\log_22^3=7.\log_22-3\log_22=7.1-3.1=4\)

a) \(\log_4\sqrt[5]{16}=\log_4\left(4^2\right)^{\dfrac{1}{5}}=\log_44^{\dfrac{2}{5}}=\dfrac{2}{5}\log_44=\dfrac{2}{5}.1=\dfrac{2}{5}\)

b) \(36^{\log_68}=\left(6^2\right)^{\log_68}=6^{2\log_68}=6^{\log_68^2}=8^2=64\)

a) \(\log_381=\log_33^4=4\log_33=4.1=4\)

b) \(\log_{10}\dfrac{1}{100}=\log_{10}10^{-2}=-2\log_{10}10=-2.1=-2\)

Program UCLN;

uses crt;

var a,b,x,y,tg: integer;

begin

clrscr;

write('Nhap a: '); readln(a); x:=a;

rite('Nhap b: '); readln(b); y:=b;

while a<>b do if a>b then a:=a-b else b:=b-a;

write('UCLN(',x,';',y,') = ',a);

Readln;

end.