Trả lời:
\(3x^2-2x=5\left(3x-2\right)\)
\(\Leftrightarrow x\left(3x-2\right)=5\left(3x-2\right)\)
\(\Leftrightarrow x\left(3x-2\right)-5\left(3x-2\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\3x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{2}{3}\end{matrix}\right.\)
Vậy x = 5; x = 2/3 là nghiệm của pt.
b, \(\left(2x-6\right)^2-x^2=0\)
\(\Leftrightarrow\left(2x-6-x\right)\left(2x-6+x\right)=0\)
\(\Leftrightarrow\left(x-6\right)\left(3x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-6=0\\3x-6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=2\end{matrix}\right.\)
Vậy x = 6; x = 2 là nghiệm của pt.