x+3 phần 5 = 6-x phần -2

\(\dfrac{2}{3}x+\dfrac{1}{2}x=\dfrac{5}{12}\)

a,\(\dfrac{2}{3}x+\dfrac{1}{2}x=\dfrac{5}{12}\)
b, x+3/5=6-x/-2
c,2x-5/7=3+x/-5

a,(2x - \(\dfrac{1}{2}\))³ = -27
b, 2^x-1+3³=5²+10

a,x² + \(\dfrac{-9}{25}\) = \(\dfrac{2}{5}\) : \(\dfrac{5}{8}\)
b,(2x - \(\dfrac{1}{5}\))² + 1\(\dfrac{9}{25}\)=2