HOC24
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Sửa Latex:
\(\text{Δ φ}=\dfrac{\text{2 π d}}{\text{λ}}=\dfrac{\text{π}}{2}\Rightarrow d=\dfrac{\text{λ}}{4}10cm\)
Ta có:
\(\dfrac{2\text{π }x}{\text{λ}}=2\text{π}.0,025x\Rightarrow\text{λ}=40cm \)
\(\text{Δ φ}=\dfrac{2\text{π}d}{\text{λ}}=\dfrac{\text{\text{π}}}{2}\Rightarrow d=\dfrac{\text{λ}}{4}=10cm\)
Chu kỳ dao động:
\(T=2\text{π }\sqrt{\dfrac{l_1+l_2}{g}}\Rightarrow T^2=\left(2\text{π }\right)^2=\dfrac{l_1+l_2}{g}=T^2_1+T_2^2\)
\(T'=2\text{π }\sqrt{\dfrac{l_1-l_2}{g}}\Rightarrow T'^2=\left(2\text{π }\right)^2\dfrac{l_1-l_2}{g}=T^2_1-T^2_2\)
\(\Rightarrow\left\{{}\begin{matrix}T^2_1+T^2_2=2,7^2\\T^2_1-T_2^2=0,9^2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}T_1=2s\\T_2=1,8s\end{matrix}\right.\)
1. Tần số của dòng điện bằng tần số điện áp:
\(f=\dfrac{\text{ω}}{2\text{π}}=50Hz\)
2. Cường độ hiệu dụng dòng điện:
\(I=\dfrac{I_0}{\sqrt{2}}=\dfrac{4}{\sqrt{2}}=2\sqrt{2}A\)
a/
Program baitap;
Uses crt;
Begin
Clrscr;
Writeln('Dien tich HCN:', 4*5);
Writeln('Chu vi HCN:', (4+5)*2);
Readln
End.
b/
Var a,b:real;
Write('Nhap chieu dai va chieu rong:');
Readln(a,b);
Writeln('Dien tich HCN:', a*b);
Writeln('Chu vi HCN:', (a+b)*2);
1:
Program baitap1;
Var A:array[1..200] of integer;
S,i:integer;
S:=0;
For i:=1 to 10 do
Write('A[',i,']=');
Readln(A[i]);
If (A[i] mod 2=1) then S:=S+A[i];
End;
Writeln('Tong cac phan tu co gia tri le:',S);
2:
Program baitap2;
For i:=1 to 15 do
If (A[i] mod 2=0) then S:=S+A[i];
Writeln('Tong cac phan tu co gia tri chan:',S);
1. D
2. D
1. has already watched
2. Has he written
3. have travelled
4.haven't given
5.hasn't seen
6.have been
7.has rained
8.hasn't had
9.hasn't played
10.have you known
11. Have you taken
12.Has she eat
13.has lost
14.have - left - has left
15.have walked
16.hasn't came
17.Have - been
18.has been
16. C
17. B
18. C
19. D
20. B
I.
2. A
3. C
4. D
5. C
II.
6. C
7. D
8. C
9. C
10. D