7.3x+20.3x=325
a) 210 : x - \(\dfrac{1}{2}\) = 20,5
b) 7.3x + 20.3x = 325
`@` `\text {Ans}`
`\downarrow`
`a)`
`210 \div x - 1/2 = 20,5`
`=> 210 \div x = 20,5 + 1/2`
`=> 210 \div x =21`
`=> x = 210 \div 21`
`=> x = 10`
Vậy, `x = 10.`
`b)`
`7 * 3^x + 20*3^x = 3^25`
`=> 3^x * (7+20) = 3^25`
`=> 3^x * 27 = 3^25`
`=> 3^x * 3^3 = 3^25`
`=> 3^x = 3^25 \div 3^3`
`=> 3^x = 3^22`
`=> x = 22`
Vậy, `x = 22.`
a) \(210:x-\dfrac{1}{2}=20,5\)
\(\Rightarrow210:x=20,5+\dfrac{1}{2}\)
\(\Rightarrow210:x=21\)
\(\Rightarrow x=\dfrac{210}{21}\)
\(\Rightarrow x=10\)
b) \(7\cdot3^x+20\cdot3^x=3^{25}\)
\(\Rightarrow3^x\cdot\left(7+20\right)=3^{25}\)
\(\Rightarrow3^x\cdot27=3^{25}\)
\(\Rightarrow3^x\cdot3^3=3^{25}\)
\(\Rightarrow3^{x+3}=3^{25}\)
\(\Rightarrow x+3=25\)
\(\Rightarrow x=25-3\)
\(\Rightarrow x=22\)
\(a)\)
\(210:x-\dfrac{1}{2}=20,5\)
\(210:x=20,5+\dfrac{1}{2}\)
\(210:x=21\)
\(x=210:21\)
\(x=10\)
Vậy \(x=10\)
\(b)\)
\(7.3^x+20.3^x=3^{25}\)
\(3^x.\left(7+20\right)=3^{25}\)
\(3^x.27=3^{25}\)
\(3^x.3^3=3^{25}\)
\(3^x=3^{25}:3^3\)
\(3^x=3^{22}\)
\(x=22\)
Vậy \(x=22\)
x-(20.3x)=x+7
=> x-(x+7)=20.3x
20.3x=-7
3x=-7/20
x=-7/60
2/3.3x+1 - 7.3x = -405
\(\dfrac{2}{3}\cdot3^{x+1}-7\cdot3^x=-405\)
\(\Rightarrow3^x\cdot\left(\dfrac{2}{3}\cdot3-7\right)=-405\)
\(\Rightarrow3^x\cdot\left(2-7\right)=-405\)
\(\Rightarrow3^x\cdot-5=-405\)
\(\Rightarrow3^x=-405:-5\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy: \(x=4\)
\(\Leftrightarrow3\cdot\dfrac{2}{3}\cdot3^x-7\cdot3^x=-405\)
=>\(-5\cdot3^x=-405\)
=>3^x=81
=>x=4
x thoả mãn 7.3x = 189
x =
A 3 B 9 C 6
\(7.3^x=189\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\Rightarrow x=3\)
Giải bất phương trình 7 . 3 x + 1 + 5 x + 3 ≤ 3 x + 4 + 5 x + 2
A. x ≤ -1
B. x ≥ -1
C. x ≤ 0
D. x ≥ 0
Gọi x 1 , x 2 là hai nghiệm của phương trình 9 x + 1 − 20.3 x + 8 = 0. Khẳng định nào sau đây đúng?
A. x 1 + x 2 = log 3 8 9
B. x 1 + x 2 = log 3 20 9
C. x 1 x 2 = log 3 8 9
D. x 1 x 2 = 8 9
Đáp án A
Phương trình 9 x + 1 − 20.3 x + 8 = 0 ⇔ 9 3 x 2 − 20.3 x + 8 = 0 *
Đặt t = 3 x > 0 , khi đó * ⇔ 9 t 2 − 20. t + 8 = 0 ⇒ t 1 t 2 = 8 9 ⇔ 3 x 1 .3 x 2 = 8 9 ⇔ x 1 + x 2 = log 3 8 9
Tìm x
(-x).3/2+9/7/6.(7.3x+2)=95x
7.3x *(x+1)^2 -5x^3(x+1)+7(x+1)
8.(2x+1)^2-(x-1)^2
9.(x+5)^2-(x-7)^2
10.9 (x+5)^2-(x-7)^2
1 Tìm x
a) (3/4-1/5-1/6)::1/30-|3x-3|=2
b)5/7.3x-8/5=35/9
c)13/15-(13/21+x).7?12=7/10
d)(+1/4-1/3):(2+1/6-1/4)==7/46