Tính nhanh
a/ (5/12 + 1/8 - 7/11) / (49/11 - 7/8 - 35/12)
b/ ( 5 - 5/3 - 5/9 - 5/27) / (-8 + 8/3 + 8/9 + 8/27) : (15 - 15/11 - 15/121) / (16 - 16/11 - 16/121)
\(\frac{\frac{5}{12}+\frac{1}{8}-\frac{7}{11}}{\frac{49}{11}-\frac{7}{8}-\frac{35}{12}}\)
\(\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{-8+\frac{8}{3}+\frac{8}{9}+\frac{8}{27}}:\frac{15-\frac{15}{11}-\frac{15}{121}}{16-\frac{16}{11}-\frac{16}{121}}\)
*Tìm số tự nhiên n,biết :
1)8.2^n = 128
2) 121 . 11^n = 1331
3) 7^n :49=343
1)\(8.2^n=128\Rightarrow2^n=128:8\Rightarrow2^n=16\Rightarrow2^n=2^4\Rightarrow n=4\)
2)\(121.11^n=1331\Rightarrow11^n=1331:121\Rightarrow11^n=11\Rightarrow n=1\)
3)\(7^n:49=343\Rightarrow7^n:7^2=7^3\Rightarrow7^n=7^3.7^2\Rightarrow7^n=7^5\Rightarrow n=5\)
nhớ **** cho mình nhé
Tìm số tự nhiên x, biết
a) 2 x : 2 = 8
b) 3 x : 3 2 = 243
c) 625 : 5 x = 52
d) 3 x : 27 = 9
e) 7 x + 1 : 7 = 49
f) 112 x + 1 : 11 = 121
a) x = 4
b) x = 7
c) x = 2
d) x = 5
e) x = 2
f) x= 1.
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Tìm số tự nhiên x, biết
a, 2 x : 2 = 8
b, 3 x : 3 2 = 243
c, 625 : 5 x = 5 2
d, 3 x : 27 = 9
e, 7 x + 1 : 7 = 49
f, 11 2 x + 1 : 11 = 121
a) x = 4
b) x = 7
c) x = 2
d) x = 5
e) x = 2
f) x= 1
tim x:
1)x-10/3=7/15*3/5
2)8/23.46/24*x=1/3
3)x+3/22=27/121*11/9
4)1-x=49/65*5/7
\(\frac{2}{3}.x=\frac{1}{3}\)1) x-\(\frac{10}{3}\)=\(\frac{7}{15}.\frac{3}{5}\)
x-10/3=7/25
x=7/25+10/3
x=\(\frac{271}{75}\)
2)\(\frac{8}{23}.\frac{46}{24}.x=\frac{1}{3}\)
2/3.x=1/3
x=1/3:2/3
x=1/2
mọi người ơi giúp mình câu này ạ 2/49 nhân 121 chia 22/7
\(\dfrac{2}{49}\) x 121 : \(\dfrac{22}{7}\)
= \(\dfrac{2}{49}\) x 121 x \(\dfrac{7}{22}\)
= \(\dfrac{2}{7\times7}\) \(\times\)\(\dfrac{11\times11\times7}{11\times2}\)
= \(\dfrac{11}{7}\)
\(\dfrac{2}{49}\times121:\dfrac{22}{7}\)
\(=\dfrac{2\times121}{49}\times\dfrac{7}{22}\)
\(=\dfrac{2\times121\times7}{49\times22}\)
\(=\dfrac{2\times11\times11\times7}{7\times7\times22}\)
\(=\dfrac{22\times11}{7\times22}\)
\(=\dfrac{11}{7}\)
\(\dfrac{2}{49}\times121:\dfrac{22}{7}\)
\(=\dfrac{2\times121}{49}\times\dfrac{7}{22}\)
\(=\dfrac{2\times121\times7}{49\times22}\)
\(=\dfrac{11}{7}\)
(19x+13^2):5=49
(x+7)^2=121
(-35).(x+39)=-210
giúp đi mọi người 
b: \(\Leftrightarrow\left[{}\begin{matrix}x+7=11\\x+7=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-18\end{matrix}\right.\)
\(\left(19x+13^2\right):5=49\\ \left(19x+169\right):5=49\\ 19x+169=49.5\\ 19x+169=245\\ 19x=245-169\\ 19x=76\\ x=76:19\\ x=4\)
Tính \(\log_{\sqrt[3]{7}}\frac{121}{8}\) theo \(a=\log_{49}11\) và \(b=\log_27\)
Ta có \(a=\frac{1}{2}\log_711;b=\log_27\)
Mặt khác : \(\log_{\sqrt[3]{7}}\frac{121}{8}=3\log_7\frac{11^2}{2^3}=3\left(2\log_711-3\log_72\right)=6\log_711-\frac{9}{\log_27}=12a-\frac{9}{b}\)
Vậy \(\log_{\sqrt[3]{7}}\frac{121}{8}=12a-\frac{9}{b}\)
