Mong mọi người giúp mình với ạ

\(a,y\times7+y\times3=70\\ \Rightarrow y\times\left(7+3\right)=70\\ \Rightarrow y\times10=70\\ \Rightarrow y=7\\ b,18:y+12:y=3\\ \Rightarrow\left(18+12\right):y=3\\ \Rightarrow30:y=3\\ \Rightarrow y=10\)

y x 7 + y x 3 = 70

y x ( 7 + 3 )  = 70

y x 10          = 70 : 10

y                  = 7

18 : y + 12 : y = 3

( 18 + 12 ) : y = 3

30 : y             = 3

y                    = 30 : 3

y                    = 10

SSSĐ

a: S

b: S

c: S

d: Đ

a) \(-28-7|-3x+15|=-70\)

\(\Rightarrow7|-3x+15|=42\)

\(\Rightarrow|-3x+15|=6\)

\(\Rightarrow|3\left(5-x\right)|=6\)

\(\Rightarrow|3|.|5-x|=6\)

\(\Rightarrow3|5-x|=6\)

\(\Rightarrow|5-x|=2\)

\(\Rightarrow\orbr{\begin{cases}5-x=2\\5-x=-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=3\\x=7\end{cases}}\)

Vậy \(x\in\left\{3;7\right\}\)

b) \(|18-2|-x+5||=12\)

\(\Rightarrow\orbr{\begin{cases}18-2|-x+5|=12\\18-2|-x+5|=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2|5-x|=6\\2|5-x|=30\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}|5-x|=3\left(1\right)\\|5-x|=15\left(2\right)\end{cases}}\)

Từ \(\left(1\right):\Rightarrow\orbr{\begin{cases}5-x=3\\5-x=-3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2\\x=8\end{cases}}\)

Từ \(\left(2\right):\Rightarrow\orbr{\begin{cases}5-x=15\\5-x=-15\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-10\\x=20\end{cases}}\)

Vậy \(x\in\left\{2;8;-10;20\right\}\)

c) \(12-2\left(-x+3\right)^2=-38\)

\(\Rightarrow2\left(3-x\right)^2=50\)

\(\Rightarrow\left(3-x\right)^2=100\)

\(\Rightarrow\orbr{\begin{cases}3-x=10\\3-x=-10\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-7\\x=13\end{cases}}\)

Vậy \(x\in\left\{-7;13\right\}\)

d) \(-20+3\left(2x+1\right)^3=-101\)

\(\Rightarrow3\left(2x+1\right)^3=-81\)

\(\Rightarrow\left(2x+1\right)^3=-27\)

\(\Rightarrow2x+1=-3\)

\(\Rightarrow2x=-4\)

\(\Rightarrow x=-2\)

Vậy \(x=-2\)

Trả lời:

a, -28 - 7| -3x + 15 | = -70

=> 7| -3x + 15 | = 42

=> | -3x + 15 | = 6

=> -3x + 15 = 6 hoặc -3x + 15 = -6

=>   -3x = -9                    -3x = -21

=>  x = 3                            x = 7

Vậy x = 3; x = 7

b, | 18 - 2 | -x + 5 || = 12

=> 18 - 2| -x + 5 | = 12 hoặc 18 -  2| -x + 5 | = -12

=> 2 | -x + 5 | = 6   hoặc    2 | -x + 5 | = 30

=> | -x + 5 | = 3    hoặc      | -x + 5 | = 15

=>  -x + 5 = 3 hoặc -x + 5 = -3 hoặc -x + 5 = 15 hoặc -x + 5 = -15

=>  x = 2                     x = 8                  x = -10               x = 20

Vậy x \(\in\){ 2; 8; -10; 20 }

c, 12 - 2.( -x + 3 )² = -38

=> 2.( -x + 3 )² = 50

=> ( -x + 3 )² = 25

=> -x + 3 = 5 hoặc -x + 3 = -5

=>   x = -2                x = 8

Vậy x = -2; x = 8

d, -20 + 3.( 2x + 1 )³ = -101

=> 3.( 2x + 1)³ = -81

=> ( 2x + 1 )³ = -27

=> 2x + 1 = -3 

=> 2x = -4

=> x = -2

Vậy x = -2

=> x = 1

1) \(A=\frac{7}{10\times11}+\frac{7}{11\times12}+\frac{7}{12\times13}+...+\frac{7}{69\times70}\)

    \(A=7\times\left(\frac{1}{10\times11}+\frac{1}{11\times12}+\frac{1}{12\times13}+...+\frac{1}{69\times70}\right)\)

    \(A=7\times\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)

    \(A=7\times\left(\frac{1}{10}-\frac{1}{70}\right)\)

   \(A=7\times\frac{3}{35}\)

   \(A=\frac{3}{5}\)

2) \(B=\frac{1}{25\times27}+\frac{1}{27\times29}+\frac{1}{29\times31}+...+\frac{1}{73\times75}\)

    \(B=\frac{1}{2}\times\left(\frac{2}{25\times27}+\frac{2}{27\times29}+\frac{2}{29\times31}+...+\frac{2}{73\times75}\right)\).

    \(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)

    \(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{75}\right)\)

    \(B=\frac{1}{2}\times\frac{2}{75}\)

    \(B=\frac{1}{75}\)

3) \(C=\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+...+\frac{4}{2008\times2010}\)

    \(C=\frac{4}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{2008\times2010}\right)\)

    \(C=2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)

    \(C=2\times\left(\frac{1}{2}-\frac{1}{2010}\right)\)

    \(C=2\times\frac{502}{1005}\)

    \(C=\frac{1004}{1005}\)

_Chúc bạn học tốt_

a, x = {45;60}

b, x = {35;42;49;56;63;70}

c, x = {36;54;72;90}

d, x = {36;48;60;72;84;96}

e, x = {25;30;35;40;45;50;55;60}

f, x = {27;30;33;36;39;42;45;48;51;54;57}

  hello

a, |2x+1| - 19 = -7

|2x+1| = 12

TH1: 2x + 1 = 12

2x = 11

x = \(\frac{11}{2}\)

TH2: 2x + 1 = -12

2x = -13

x = \(\frac{-13}{2}\)

b, -28 - 7.|-3x+15| = -70

-7.|-3x+15| = -42

|-3x+15| = 6

TH1: -3x + 15 = 6

-3x = -9

x = 3

TH2: -3x + 15 = -6

-3x = -21

x = 7

d, 12 - 2( -x + 3)² = -38

-2( -x + 3)² = -50

( -x + 3)² = 25

( -x + 3)² = +- 5²

-x + 3 = +- 5

TH1: -x + 3 = 5

-x = 2

x = -2

TH2: -x + 3 = -5

-x = -8

x = 8

e, -20 + 3(3x+1)³ = -101

3(3x+1)³ = -81

(3x+1)³ = -27

(3x+ 1)³ = -3³

3x + 1 = -3

3x = -4

x = \(\frac{-4}{3}\)

Chúc bạn học tốt !

hello

a, |2x+1|-19= -7

a, Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{7}=\dfrac{y}{12}=\dfrac{x+y}{7+12}=\dfrac{10}{19}\)

\(\dfrac{x}{7}=\dfrac{10}{19}\Rightarrow x=\dfrac{70}{19}\\ \dfrac{y}{12}=\dfrac{10}{19}\Rightarrow y=\dfrac{120}{19}\)

b,\(4x=3y\Rightarrow\dfrac{x}{3}=\dfrac{y}{4}\)

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x+y}{3+4}=\dfrac{70}{7}=10\)

\(\dfrac{x}{3}=10\Rightarrow x=30\\ \dfrac{y}{4}=10\Rightarrow y=40\)

a.x/5=y/4=z/6-2y=-2
b.5x=4y=6z và x-y-z =-78
c.x/7=y/10 4/6=z/4 và x-y+z=33
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