\(\dfrac{1}{72}\) x \(\dfrac{144}{23}\)+ \(\dfrac{1}{46}\)
\(\dfrac{1}{72}\) x \(\dfrac{144}{23}\) + \(\dfrac{1}{46}\)
Ôn tập lain kiến thức lớp bốn:)
\(\dfrac{1}{24}x\dfrac{72}{23}+\dfrac{1}{46}\). \(\dfrac{9}{11}+\dfrac{1}{12}:\dfrac{11}{24}\). \(\dfrac{4}{7}-\dfrac{1}{5}x\dfrac{5}{9}\)
Một mảnh đất hình thoi có tổng độ dai hai đường chéo là 180m . Đường chéo thứ nhất hơn đường chéo thứ hai là 24m. TÍNH DIỆN TÍCH MẢNH ĐẤT HÌNH THOI ĐÓ .
AI NHỚ KIẾN THỨC SSEN XUON DƯỚI NHÉ
3/23 + 1/46 = 7/46
9/11 + 2/11 = 11/11 = 1
4/7 - 1/9 = 29/63
1/24 x 72/23 +1/46=7/46
9/11 +1/12 :11/24=1
4/5-1/5x5/9=29/63
giải
đường chéo T1 là
(180+24):2=102(m2)
đường chéo T2 là
180-102=78(m2)
diệnt ích mảnh đất là
\(\dfrac{102x78}{2}=3978\left(m^2\right)\)
\(\dfrac{8}{23}.\dfrac{46}{24}=\dfrac{1}{3}.x\)
\(\Rightarrow\dfrac{2}{3}=\dfrac{1}{3}.x\)
\(\Rightarrow x=\dfrac{2}{3}:\dfrac{1}{3}\)
\(\Rightarrow x=2\)
\(\dfrac{8}{23}.\dfrac{46}{24}=\dfrac{1}{3}x\\ \Rightarrow\dfrac{1}{3}x=\dfrac{2}{3}\\ \Rightarrow x=\dfrac{2}{3}:\dfrac{1}{3}\\ \Rightarrow x=2\)
Tìm x \(\in\) Z biết :
a ) \(\dfrac{1}{2}-\) (\(\dfrac{1}{2}-\dfrac{3}{2}\) ) \(\le x\le\dfrac{37}{24}-\left(\dfrac{1}{8}-\dfrac{2}{3}\right)\)
b ) \(\dfrac{-1}{23}+\dfrac{9}{-69}-\dfrac{7}{23}< \dfrac{x}{23}\le\dfrac{2}{46}-\dfrac{8}{23}\)
giúp mình với
a: \(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{2}+\dfrac{3}{2}\le x\le\dfrac{37}{24}-\dfrac{3-16}{24}=\dfrac{37-3+16}{24}=\dfrac{50}{24}=\dfrac{25}{12}\)
=>3/2<=x<=25/12
mà x là số nguyên
nên x=2
b: \(\Leftrightarrow-\dfrac{1}{23}-\dfrac{3}{23}-\dfrac{7}{23}< x\le\dfrac{1}{23}-\dfrac{8}{23}\)
=>-11<x<=-7
mà x là số nguyên
nên \(x\in\left\{-10;-9;-8;-7\right\}\)
\(B=\dfrac{\left(\dfrac{11^2}{200}+0,415\right):0,01}{\dfrac{1}{12}-37,25+3\dfrac{1}{6}}\) tính B
tìm X
\(\dfrac{-9}{46}-4\dfrac{1}{23}:\left(3\dfrac{1}{4}-x:\dfrac{3}{5}\right)+2\dfrac{8}{23}=1\)
câu dễ như này sao bạn không tự giải ? cứ phụ thuộc vào người khác thôi
\(\dfrac{3}{46}\)+\(\dfrac{4}{23}\)-\(\dfrac{1}{115}\)
\(\dfrac{3}{46}+\dfrac{4}{23}-\dfrac{1}{115}=\dfrac{15}{230}+\dfrac{40}{230}-\dfrac{2}{230}=\dfrac{53}{230}\)
\(\dfrac{3}{46}+\dfrac{4}{23}-\dfrac{1}{115}\\ \\ =\dfrac{3}{46}+\dfrac{8}{46}-\dfrac{1}{115}\\ \\ =\dfrac{11}{46}-\dfrac{1}{115}\\ \\ =\dfrac{53}{230}\)
\(...=\dfrac{15}{230}+\dfrac{40}{230}+\dfrac{2}{230}=\dfrac{57}{230}\)
\(\dfrac{-9}{46}\)-4\(\dfrac{1}{23}\):(3\(\dfrac{1}{4}\)-x:\(\dfrac{3}{5}\))+2\(\dfrac{8}{23}\)=1
\(\dfrac{-9}{46}\)-4\(\dfrac{1}{23}\)\(\div\)(3\(\dfrac{1}{4}\)-x\(\div\)\(\dfrac{3}{5}\))+2\(\dfrac{8}{23}\)=1
\(\Leftrightarrow-\dfrac{93}{23}:\left(\dfrac{13}{4}-x\cdot\dfrac{5}{3}\right)=1-\dfrac{99}{46}=-\dfrac{53}{46}\)
\(\Leftrightarrow\dfrac{13}{4}-\dfrac{5}{3}x=-\dfrac{99}{23}:-\dfrac{53}{46}=\dfrac{198}{53}\)
=>5/3x=-103/212
hay x=-309/1060
Bài 1 : tìm x
a) \(\dfrac{2012-x}{25}+\dfrac{2053-x}{23}+\dfrac{2070-x}{21}+\dfrac{2083-x}{19}-10=0\\ \)
b) \(x+\dfrac{13}{12}+\dfrac{21}{20}+\dfrac{31}{30}+\dfrac{43}{42}+\dfrac{57}{56}+\dfrac{73}{72}+\dfrac{91}{90}=0\)
a: \(\dfrac{2032-x}{25}+\dfrac{2053-x}{23}+\dfrac{2070-x}{21}+\dfrac{2083-x}{19}-10=0\)
\(\Leftrightarrow\left(\dfrac{2032-x}{25}-1\right)+\left(\dfrac{2053-x}{23}-2\right)+\left(\dfrac{2070-x}{21}-3\right)+\left(\dfrac{2083-x}{19}-4\right)=0\)
=>2007-x=0
hay x=2007
b: \(\Leftrightarrow x+\left(1+1+1+1+1+1+1\right)+\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)=0\)
\(\Leftrightarrow x+7+\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)=0\)
=>x+7+1/3-1/10=0
hay x=-217/30