a, 3x2 - 8x2 - 2x+3=0

2x(3-8) - 2x+3=0

2x5 - 2x+3=0

2x5 - 2x=0-3=

2x5 - 2x=-3

2x(5-x)=-3

5-x=-3/2

5-x=1,5

x=5-1,5

x=3,5

3,5 nha bn

chúc bn học tốt

happy new year

bạn tách từng bài ra bn

tl câu hỏi trên cho mik ik

kh hiểu bn ơi

`4x=2+xx+1x<=>4x=2+3x<=>4x-3x=2<=>1x=2<=>x=2`

a: =>2^x*4-2^x*3=32

=>2^x=32

=>x=5

b: =>(4x-3)^2-(4x-3)=0

=>(4x-3)(4x-3-1)=0

=>(4x-3)(4x-4)=0

=>x=3/4 hoặc x=1

c: =>7^2x+7^2x*7^3=344

=>7^2x=1

=>2x=0

=>x=0

d: =>(7x-3)^2012-(7x-3)^2010=0

=>(7x-3)^2010*[(7x-3)^2-1]=0

=>(7x-3)^2010*(7x-4)(7x-2)=0

=>x=2/7; x=4/7; x=3/7

e: =>(4x^2-3)^3=-8

=>4x^2-3=-2

=>4x^2=1

=>x^2=1/4

=>x=1/2 hoặc x=-1/2

a) 2^x(2² - 3) = 32

2^x.1=2⁵

=> x = 5

b) (4x - 3)² = 4x -3

=> (4x - 3)² - (4x - 3) = 0

(4x-3)[(4x - 3) - 1] = 0

(4x-3)(4x - 4)=0

\(\Rightarrow\left[{}\begin{matrix}4x-3=0\\4x-4=0\end{matrix}\right.\)         \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=1\end{matrix}\right.\)

c) 7^2x + 7^2x+3 = 344

=> 7^2x(1 + 7³) =344

7^2x . 344 = 344

=> 2x = 0  => x = 0

d) (7x - 3)²⁰¹² = (3 - 7x)²⁰¹⁰

=> (7x - 3)²⁰¹² - (7x - 3)²⁰¹⁰ = 0

(7x - 3)²⁰¹⁰ [(7x - 3)² - 1] = 0

\(\Rightarrow\left[{}\begin{matrix}7x-3=0\\\left(7x-3\right)^2=1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{7}\\7x=4\\7x=2\end{matrix}\right.\)                 \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{7}\\x=\dfrac{4}{7}\\x=\dfrac{2}{7}\end{matrix}\right.\)

e) (4x² - 3)³ + 8 = 0

(4x² - 3)³ = (-2)³

=> 4x² - 3 = -2

4x² = 1

x² = 1/4

=> \(x=\pm\dfrac{1}{2}\)

bài lạ thật

ý bạn là như thế này đúng không ạ:

a/ \(x^2-6x+5=0\)

\(x^2-5x-x+5=0\)

\(x\left(x-5\right)-\left(x-5\right)=0\)

\(\left(x-5\right)\left(x-1\right)=0\)

\(\orbr{\begin{cases}x-5=0\rightarrow x=5\\x-1=0\rightarrow x=1\end{cases}}\)

b/\(2x^2+7x+9=0\)

?!

c/ \(4x^2-7x+3=0\)

\(4x^2-4x-3x+3=0\)

\(4x\left(x-1\right)-3\left(x-1\right)=0\)

\(\left(x-1\right)\left(4x-3\right)=0\)

\(\orbr{\begin{cases}x-1=0\Rightarrow x=1\\4x-3=0\Rightarrow x=\frac{3}{4}\end{cases}}\)

d/ \(2\left(x+5\right)=2x+10\)

-,- mik ko rõ đề ạ, sai thì ibox ạ.Cảm ơn

x2−6x+5=0

2x2+7x+9=0

4x2−7x+3=0

2(x+5)=x2+5x

a) x=0

b) x=0

c) x=0

d)x=x

a b c d 

x=x

\(x^2-6x+5=0\)

\(\Leftrightarrow x^2-x-5x+5=0\)

\(\Leftrightarrow x\left(x-1\right)-5\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\x-5=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=5\end{cases}}\)

\(2x^2+7x+9=0\)

Đề sai??

\(4x^2-7x+3=0\)

\(\Leftrightarrow4x^2-4x-3x+3=0\)

\(\Leftrightarrow4x\left(x-1\right)-3\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(4x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\4x-3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{3}{4}\end{cases}}\)

\(2\left(x+5\right)=x^2+5x\)

\(\Leftrightarrow2x+10=x^2+5x\)

\(\Leftrightarrow x^2+5x-2x-10=0\)

\(\Leftrightarrow x^2+3x-10=0\)

\(\Leftrightarrow x^2+5x-2x-10=0\)

\(\Leftrightarrow x\left(x+5\right)-2\left(x+5\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+5=0\\x-2=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-5\\x=2\end{cases}}\)

x3+4x2-7x-10=0

x3+8x-7x=10

x(3+8-7)=10

x4=10

x=10:4

x=2,5

số 3 với số 2 là số mũ nhé

wtf???????????????????