Tìm x:

\(a.\dfrac{35}{28}-x=\dfrac{5}{14}\\ x=\dfrac{35}{28}-\dfrac{5}{14}\\ x=\dfrac{25}{28}\\ b.\dfrac{6}{7}\times x=\dfrac{2}{3}\\ x=\dfrac{2}{3}:\dfrac{6}{7}\\ x=\dfrac{7}{9}\\ c.x\times7=\dfrac{3}{4}\\ x=\dfrac{3}{4}:7\\ x=\dfrac{3}{28}\\ d.2:x-\dfrac{1}{3}=\dfrac{2}{5}\\ 2:x=\dfrac{2}{5}+\dfrac{1}{3}\\ 2:x=\dfrac{11}{15}\\ x=2:\dfrac{11}{15}\\ x=\dfrac{30}{11}.\)

\(a,\dfrac{35}{28}-x=\dfrac{5}{14}\)

\(x=\dfrac{35}{28}-\dfrac{5}{14}\)

\(x=\dfrac{25}{28}\)

\(b,\dfrac{6}{7}\times x=\dfrac{2}{3}\)

\(x=\dfrac{2}{3}:\dfrac{6}{7}\)

\(x=\dfrac{7}{9}\)

\(c,x\times7=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:7\)

\(x=\dfrac{3}{28}\)

\(d,2:x-\dfrac{1}{3}=\dfrac{2}{5}\)

\(2:x=\dfrac{2}{5}+\dfrac{1}{3}\)

\(2:x=\dfrac{11}{15}\)

\(x=2:\dfrac{11}{15}\)

\(x=\dfrac{30}{11}\)

#YVA

\(a,\dfrac{5}{8}-x=\dfrac{4}{7}\times\dfrac{1}{4}\\ \dfrac{5}{8}-x=\dfrac{4\times1}{7\times4}\\ \dfrac{5}{8}-x=\dfrac{4}{28}\\ \dfrac{5}{8}-x=\dfrac{1}{7}\\ x=\dfrac{5}{8}-\dfrac{1}{7}\\ x=\dfrac{5\times7}{8\times7}-\dfrac{1\times8}{7\times8}\\ x=\dfrac{35}{56}-\dfrac{8}{56}\\ x=\dfrac{35-8}{56}\\ x=\dfrac{27}{56}\\ b,x:\dfrac{4}{5}=\dfrac{3}{4}+\dfrac{1}{6}\\ x:\dfrac{4}{5}=\dfrac{3\times3}{4\times3}+\dfrac{1\times2}{6\times2}\\ x:\dfrac{4}{5}=\dfrac{9}{12}+\dfrac{2}{12}\\ x:\dfrac{4}{5}=\dfrac{9+2}{12}\\ x:\dfrac{4}{5}=\dfrac{11}{12} \\ x=\dfrac{11}{12}\times\dfrac{4}{5}\\ x=\dfrac{11\times4}{12\times5}\\ x=\dfrac{44}{60}=\dfrac{11}{15}\)

a: =>5/8-x=1/7

=>x=5/8-1/7=35/56-8/56=27/56

b: =>x:4/5=9/12+2/12=11/12

=>x=11/12*4/5=44/48=11/12

a) x=4/2

b) x=1/12

c) 24/35

a,\(\dfrac{1}{2}+x=\dfrac{5}{2}\)

\(x=\dfrac{5}{2}-\dfrac{1}{2}\)

\(\Rightarrow x=2\)

b,\(\dfrac{3}{4}-x=\dfrac{2}{3}\)

\(x=\dfrac{3}{4}-\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{1}{12}\)

c,\(x:\dfrac{4}{5}=\dfrac{6}{7}\)

\(x=\dfrac{6}{7}.\dfrac{4}{5}\)

\(\Rightarrow\dfrac{24}{35}\)

a)1/2+x=5/2                                          b)3/4-x=2/3

    x=5/2-1/2=4/2=2                                  x=3/4-2/3=1/12

c)x:4/5=6/7

   x=6/7.4/5=24/35

a: =>4x-5=0 hoặc 5/4x-2=0

=>x=5/4 hoặc x=2:5/4=2*4/5=8/5

b: =>(1/12+19/6-30,75)*x-8=102

=>-55/2x=110

=>x=-4

3/5

1 1/6 

a 4/5 - X = 3/15

X = 4/5 - 3/15

X = 3/5

b X : 2/3 = 1/2

X = 1/2 x 2/3

X = 11/6 

3/5

11/6

a) \(\left(x+1\right)^3-\left(x-1\right)^3-6\cdot\left(x-1\right)^2=10\)

\(\Rightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\cdot\left(x^2-2x+1\right)=10\)

\(\Rightarrow6x^2+2-6x^2+12x-6=10\)

\(\Rightarrow12x-4=10\)

\(\Rightarrow12x=14\)

\(\Rightarrow x=\dfrac{7}{6}\)

b) \(x\left(x+5\right)\left(x-5\right)-\left(x+2\right)\left(x^2-2x+4\right)=42\)

\(\Rightarrow x\left(x^2-25\right)-\left(x^3+8\right)=42\)

\(\Rightarrow x^3-25x-x^3-8=42\)

\(\Rightarrow-25x-8=42\)

\(\Rightarrow-25x=50\)

\(\Rightarrow x=\dfrac{50}{-25}=-2\)

c) \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)

\(\Rightarrow x^3-6x^2+12x-8-\left(x^3-27\right)+6\left(x^2+2x+1\right)=49\)

\(\Rightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\)

\(\Rightarrow24x+25=49\)

\(\Rightarrow24x=24\)

\(\Rightarrow x=\dfrac{24}{24}=1\)

Lời giải:

a.

$\frac{2}{3}+\frac{1}{3}:3\times x=20\text{%}$
$\frac{2}{3}+\frac{1}{9}\times x=\frac{1}{5}$

$\frac{1}{9}\times x=\frac{1}{5}-\frac{2}{3}=\frac{-7}{15}$

$x=\frac{-7}{15}: \frac{1}{9}=\frac{-21}{5}$
b.

$\frac{3-x}{5-x}=\frac{6}{11}$
$\Rightarrow 6(5-x)=11(3-x)$

$\Rightarrow 30-6x=33-11x$

$\Rightarrow 5x=3$

$\Rightarrow x=\frac{3}{5}$

\(a,\Leftrightarrow x^3=\dfrac{20}{3}\Leftrightarrow x=\sqrt[3]{\dfrac{20}{3}}\\ b,\Leftrightarrow x-1=9\Leftrightarrow x=10\\ c,\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\\ d,\Leftrightarrow2x+1=5\Leftrightarrow x=2\\ e,\Leftrightarrow2x-4=4\Leftrightarrow x=4\)

Câu a) xem lại đề giùm nhé em

b) \(\left(x-1\right)^3=9^3\)

\(x-1=9\)

\(x=10\)

Vậy \(x=10\)

c) \(\left(x-1\right)^2=25\)

\(x-1=5\) hoặc \(x-1=-5\)

* \(x-1=5\)

\(x=6\)

* \(x-1=-5\)

\(x=-4\)

Vậy \(x=-4\); \(x=6\)

d) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

Vậy \(x=2\)

e) Sửa đề: \(\left(2x+4\right)^3=64\)

\(\left(2x+4\right)^3=4^3\)

\(2x+4=4\)

\(2x=0\)

\(x=0\)

Vậy \(x=0\)

\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)

a: =>6/x=3/8

hay x=16

b: =>x/27=1/9

nên x=3

c: =>4/x=4/3

nên x=3

d: =>3/x-5=-4/x+2

=>3x+2=-4x+20

=>7x=18

hay x=18/7

Bài 3: 

Gọi số nhóm là x

Theo đề, ta có: \(x\in\left\{1;2;3;4;6;9;12;18;36\right\}\)

mà 2<x<6

nên \(x\in\left\{3;4\right\}\)

Vậy: Có 2 cách chia nhóm

a) 25 - x = 12 + 6  =18

x=25-18=7 Vậy x=7

b) 7 + 2 x ( x -3 ) = 11   

2.(x-3)=11-7=4

x-3=4:2=2

x=3+2=5                          

c) 102 : ( 2.x + 13) : 4) = 6   

(2.x+13):4=102:6=17

2.x+13=17.4=68

2.x=68-13=55

x=27,5 Vậy x=27,5

Bài 3: 

Gọi số nhóm là x

Theo đề, ta có: 

mà 2<x<6

nên 

Vậy: Có 2 cách chia nhóm

còn bài 1 chắc bn làm đc nha tick mk nha