a: =>4x-5=0 hoặc 5/4x-2=0
=>x=5/4 hoặc x=2:5/4=2*4/5=8/5
b: =>(1/12+19/6-30,75)*x-8=102
=>-55/2x=110
=>x=-4
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Tìm x biết: a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\) b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)
c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\) d) \(x+\dfrac{1}{3}=\dfrac{-12}{5}.\dfrac{10}{6}\)
Tìm x biết:
(1/12+19/6-30,75).x-8=(3/5+0,415+1/200);0,01
Tìm xa/dfrac{x}{5}+dfrac{1}{2}dfrac{6}{10}b/dfrac{1}{2}.x+dfrac{1}{2}dfrac{5}{2}c/dfrac{1}{2}-dfrac{2}{3}.xdfrac{7}{12}giúp e ạ
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Tìm x
a/\(\dfrac{x}{5}\)+\(\dfrac{1}{2}\)=\(\dfrac{6}{10}\)
b/\(\dfrac{1}{2}\).\(x\)+\(\dfrac{1}{2}\)=\(\dfrac{5}{2}\)
c/\(\dfrac{1}{2}\)-\(\dfrac{2}{3}\).\(x\)=\(\dfrac{7}{12}\)
giúp e ạ
11 tháng 7 2023 lúc 9:25
Tìm x:
a) \(\dfrac{5}{4}+\left(2x-\dfrac{1}{2}\right)=\dfrac{5}{6}\)
b) \(\dfrac{3}{2}-\left(x+\dfrac{1}{4}\right)=\dfrac{5}{8}\)
c) \(\dfrac{x}{3}=\dfrac{12}{x}\)
Giúp với!
Tìm x, biết:
a) x+\(\dfrac{1}{6}\)=\(\dfrac{-3}{8}\) b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
c) \(\dfrac{1}{2}x\)+\(\dfrac{1}{8}x=\dfrac{3}{4}\) d) 75%-\(1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
Bài3:Tìm x
a,\(\dfrac{x}{7}\)=\(\dfrac{6}{12}\) b,\(\dfrac{-5}{x}\)=\(\dfrac{20}{28}\) c,\(\dfrac{x-2}{8}\)=\(\dfrac{3}{4}\) d,\(\dfrac{x}{-5}\)=\(\dfrac{-5}{x}\)
các ban giúp mình nha, cảm ơn các bạn
bài 1 tìm x
a. 5 - 3(x+4) = -1
b.(x-1) - (x+2) = 0
c.( \(\dfrac{1}{2}\) + x )-( \(\dfrac{1}{3}\) - x) = 0
d. 2x2 - 3 = 5
e. x(2x -1) = 0
g. \(\dfrac{1}{3}\) . x2 - \(\dfrac{1}{6}\)=\(\dfrac{7}{6}\)
Tìm x
a) 4/5 ( x - 1/3) - \(3\dfrac{1}{2}\)= 50%
b) \(8\dfrac{3}{5}\cdot x-2\dfrac{1}{5}\cdot x=16\%\)
Tìm x biết: a) dfrac{6}{-x}dfrac{x}{-24} b) x-dfrac{7}{12}x+dfrac{3}{8}xdfrac{5}{24} c)left(x-dfrac{1}{3}right)^2-dfrac{1}{2}1dfrac{3}{4} d) dfrac{x-3}{-2}dfrac{-8}{x-3} e) dfrac{9}{x}dfrac{-35}{105} f) left(x-dfrac{1}{2}right)left(-3-dfrac{x}{2}right)0
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Tìm x biết: a) \(\dfrac{6}{-x}=\dfrac{x}{-24}\) b) \(x-\dfrac{7}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
c)\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\) d) \(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
e) \(\dfrac{9}{x}=\dfrac{-35}{105}\) f) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)