\(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\Leftrightarrow\dfrac{x}{5}=\dfrac{6}{10}-\dfrac{1}{2}\Rightarrow x=\dfrac{1}{10}\)
\(\dfrac{1}{2}.x+\dfrac{1}{2}=\dfrac{5}{2}\Leftrightarrow\dfrac{1}{2}.x=\dfrac{5}{2}-\dfrac{1}{2}\Leftrightarrow\dfrac{1}{2}.x=2\Leftrightarrow x=4\)
\(\dfrac{1}{2}-\dfrac{2}{3}.x=\dfrac{7}{12}\Leftrightarrow\dfrac{2}{3}.x=\dfrac{1}{2}+\dfrac{7}{12}\Leftrightarrow\dfrac{2}{3}.x=\dfrac{13}{12}\Leftrightarrow x=\dfrac{13}{12}:\dfrac{2}{3}\Leftrightarrow x=\dfrac{13}{8}\)
Giải:
a)x/5+1/2=6/10
x/5+1/2=3/5
x/5=3/5-1/2
x/5=1/10
=>x.2/10=1/10
=>x.2=1
x=1:2
x=1/2
b)1/2.x+1/2=5/2
1/2.x+1/2.1=5/2
1/2.(x+1)=5/2
x+1=5/2:1/2
x+1=5
x=5-1
x=4
c)1/2-2/3.x=7/12
2/3.x=1/2-7/12
2/3.x=-1/12
x=-1/12:2/3
x=-1/8
Chúc e học tốt!
a) Ta có: \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{6}{10}-\dfrac{1}{2}=\dfrac{1}{10}\)
hay \(x=\dfrac{1}{2}\)
Vậy: \(x=\dfrac{1}{2}\)