Tính hợp lí:
a) 10 17 − 5 13 + 7 17 − 8 13
b) 30 51 − 20 52 + 14 34 − 56 91 − 2
Tính một cách hợp lí:
a) 12 +13 + 14 - 15 - 16 - 17;
b) (35-17) - (25 - 7 + 22).
a) 12 + 13 + 14 - 15 - 16 - 17
= (12 - 15) + (13 - 16) + (14 - 17)
= (-3) + (-3) + (-3) = -9
b) (35 - 17) - (25 - 7 + 22)
= 35 - 17 - 25 + 7 - 22
= (35 - 25) - (17 - 7) - 22
= 10 - 10 - 22 = -22
Tính một cách hợp lí:
a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111};\)
b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19};\)
c) \(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}.\)
\(a.\)
\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)
\(b.\)
\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)
\(c.\)
\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)
a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\)
b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\)
c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)
Tính hợp lí:
a)11+(-13)+15+(-17)
b)(-21)+24+(-27)+31
a) 11 + ( -13 ) + 15 + ( -17 )
= 11 - 13 + 15 - 17 = ( 11 + 15 ) - ( 13 + 17 )
= 26 - 30 = - 4
b) ( -21 ) + 24 + ( -27 ) + 31
= 24 - 21 - 27 + 31 = ( 31 - 21 ) - ( 27 - 24 )
= 10 - 3 =7
Bài 4: Tìm x, biết:
a) 11 + x : 5 = 13 b) 15 + (7 – x) = 19
c) 12 + 3.(x – 5) = 30 d) 17 + (x + 4) : 3 = 21
Bài 5: Tính hợp lí:
a) 120.15 + 12.470 + 12.38.10 b) 13.58.4 + 32.26.2 + 52.10
c) 3,2.990 + 32 d) 45.(13 + 78) + 9.(87 + 22).5
e) (24 + 72 + 36 + 60) : 12
f) (2 + 4 + 6 + … + 100).(36.333 – 108.111)
1.
a.
11 + x : 5 = 13
x : 5 = 13 - 11
x : 5 = 2
x = 2 . 5
x = 10
Bài 4: Tìm x, biết:
a) 11 + x : 5 = 13
x : 5 = 2
x = 10
b) 15 + (7 – x) = 19
7 - x = 4
x = 3
c) 12 + 3.(x – 5) = 30
3 ( x - 5 ) = 18
x - 5 = 6
x = 11
d) 17 + (x + 4) : 3 = 21
( x + 4 ) : 3 = 4
x + 4 = 12
x = 8
Bài 1:Tính 1 cách hợp lí:
a) 386 - ( 287 + 386 ) - ( 13 + 0 )
b) 332 - ( 681 + 232 - 431 )
Bài 2: Bỏ ngoặc rồi tính :
a) (27 + 65 ) + ( 364 - 27 - 65 )
b) (42 - 69 + 17 ) - (42 + 17 )
Bài 1:
a, 386-287 -386 -13
= (386-386) -287-13
= 0 -300
=-300
b, =332-681 -232+431
= (332 -232) +(431-681)
= 100 - 250
= -150
Bài 2
a, = 27+65+ 364-27-65
= (27-27) +(65-65) +364
= 0+0+ 364
=364
b, = 42-69+17 -42-17
= (42-42) + (17-17) -69
= -69
chúc bạn học tốt nha!
Tính hợp lí
1) \((\)\(\dfrac{7}{-18}\)+\(\dfrac{-5}{12}\)) -\(\dfrac{13}{-18}\)
2) \(\dfrac{-13}{17}\)+(\(\dfrac{13}{-21}\)+\(\dfrac{-4}{17}\))
3) ( \(\dfrac{13}{-10}\)-\(\dfrac{-4}{13}\))+\(\dfrac{11}{-10}\)
4) \(\dfrac{13}{17}\)\(\times\)\(\dfrac{4}{-5}\)+\(\dfrac{13}{17}\)\(\times\)\(\dfrac{-3}{4}\)
5) \(\dfrac{-5}{12}\)\(\times\)\(\dfrac{7}{-17}\)\(\times\)\(\dfrac{9}{-20}\)
6) \(\dfrac{5}{9}\)\(\times\)\(\dfrac{11}{23}\)+ \(\dfrac{11}{23}\)\(\times\)\(\dfrac{17}{9}\)\(-\)\(\dfrac{13}{9}\)\(\times\)\(\dfrac{11}{23}\)
\(1.\dfrac{-7}{18}+\dfrac{-5}{12}-\dfrac{-13}{18}\text{=}\left(\dfrac{-7}{18}-\dfrac{-13}{18}\right)+\dfrac{-5}{12}\text{=}\dfrac{1}{3}+\dfrac{-5}{12}\text{=}\dfrac{-1}{12}\)
\(2.\dfrac{-13}{17}+\dfrac{-13}{21}+\dfrac{-4}{17}\text{=}\left(\dfrac{-13}{17}+\dfrac{-4}{17}\right)+\dfrac{-13}{21}\text{=}-1+\dfrac{-13}{21}\text{=}\dfrac{-34}{21}\)
\(3.\dfrac{-13}{10}-\dfrac{-4}{13}+\dfrac{-11}{10}\text{=}\dfrac{-12}{5}-\dfrac{-4}{13}\text{=}\dfrac{-136}{65}\)
\(4.\dfrac{13}{17}\times\left(\dfrac{-4}{5}+\dfrac{-3}{4}\right)\text{=}\dfrac{13}{17}\times\dfrac{-31}{20}\text{=}\dfrac{-403}{340}\)
\(5.\left(\dfrac{-5}{12}\times\dfrac{-9}{20}\right)\times\dfrac{-7}{17}\text{=}\dfrac{3}{16}\times\dfrac{-7}{17}\text{=}\dfrac{-21}{272}\)
\(6.\dfrac{11}{23}\times\left(\dfrac{5}{9}+\dfrac{17}{9}-\dfrac{13}{9}\right)\text{=}\dfrac{11}{23}\times1\text{=}\dfrac{11}{23}\)
Tính một cách hợp lí:
a) \(\frac{4}{{15}} - \left( {2,9 - \frac{{11}}{{15}}} \right)\);
b) \(( - 36,75) + \left( {\frac{{37}}{{10}} - 63,25} \right) - ( - 6,3)\);
c) \(6,5 + \left( { - \frac{{10}}{{17}}} \right) - \left( { - \frac{7}{2}} \right) - \frac{7}{{17}}\);
d) \(( - 39,1) \cdot \frac{{13}}{{25}} - 60,9 \cdot \frac{{13}}{{25}}\).
a)
\(\begin{array}{l}\frac{4}{{15}} - \left( {2,9 - \frac{{11}}{{15}}} \right)\\ = \frac{4}{{15}} - 2,9 + \frac{{11}}{{15}}\\ = \left( {\frac{4}{{15}} + \frac{{11}}{{15}}} \right) - 2,9\\=\frac{15}{15}-2,9 \\= 1 - 2,9 = - 1,9\end{array}\)
b)
\(\begin{array}{l}( - 36,75) + \left( {\frac{{37}}{{10}} - 63,25} \right) - ( - 6,3)\\ = ( - 36,75) + 3,7 - 63,25 + 6,3\\ = \left( { - 36,75 - 63,25} \right) + \left( {3,7 + 6,3} \right)\\ = - 100 + 10 = - 90\end{array}\)
c)
\(\begin{array}{l}6,5 + \left( { - \frac{{10}}{{17}}} \right) - \left( { - \frac{7}{2}} \right) - \frac{7}{{17}}\\ = \frac{{65}}{{10}} - \frac{{10}}{{17}} + \frac{7}{2} - \frac{7}{{17}}\\ = \left( {\frac{{65}}{{10}} + \frac{7}{2}} \right) - \left( {\frac{{10}}{{17}} + \frac{7}{{17}}} \right)\\ = \left( {\frac{{65}}{{10}} + \frac{{35}}{{10}}} \right) - \frac{17}{17}\\ = \frac{100}{10}-1\\=10 - 1 = 9\end{array}\)
d)
\(\begin{array}{l}( - 39,1) \cdot \frac{{13}}{{25}} - 60,9 \cdot \frac{{13}}{{25}}\\ = \frac{{13}}{{25}}.\left( { - 39,1 - 60,9} \right)\\ = \frac{{13}}{{25}}.\left( { - 100} \right)\\ = - 52\end{array}\).
Tính một cách hợp lí:
a) 17.[29 - (- 111)] + 29.(- 17);
b) 19.43 + (- 20).43 - (- 40).
a) Ta có: \(17\cdot\left[29-\left(-111\right)\right]+29\cdot\left(-17\right)\)
\(=17\cdot\left[29+111-29\right]\)
\(=17\cdot111=1887\)
b) Ta có: \(19\cdot43+\left(-20\right)\cdot43-\left(-40\right)\)
\(=43\cdot\left(19-20\right)+40\)
\(=-43+40=-3\)
Tính một cách hợp lí:
a) 4. (1 930 + 2019) + 4.(-2019);
b) (-3).(-17) + 3. (120 - 17).
a) 4.(1 930 + 2 019) + 4.(-2 019)
= 4.(1 930 + 2 019 - 2 019)
= 4.1 930
= 7 720
b) (-3).(-17) + 3.(120 - 17)
= 3.17 + 3.(120 - 17)
= 3.(17 + 120 - 17)
= 3.120
= 360
Tính bằng cách hợp lí:
a, 387+(-224)+(-87)
b, (-75)+329+(-25)
c, 11+(-13)+15+(-17)
d, (-21)+24+(-27)+31
e, 251 +(-144)+(-151)+(-216)
f, (-137)+77+(-253)+37-47
a: =300-224=76
b: =-100+329=229