a) Có: \(3+3^2+3^3+3^4+...+3^{99}\\ =\left(3+3^2+3^3\right)+\left(3^4+3^5+3^6\right)+...+\left(3^{97}+3^{98}+3^{99}\right)\\ =\left(3+3^2+3^3\right)+3^3\left(3+3^2+3^3\right)+...+3^{97}\left(3+3^2+3^3\right)\\ =39+3^3\cdot39+...+3^{97}\cdot39\\ =13\cdot3+3^3\cdot13\cdot3+...+3^{97}\cdot13\cdot3\\ =13\left(3+3^4+...+3^{98}\right)⋮13\left(đpcm\right)\)

b) Có: \(81^7-27^9-9^{13}\\ =\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\\ =3^{28}-3^{27}-3^{26}\\ =3^{26}\left(3^2-3-1\right)\\ =3^{24}\cdot\left(3^2\cdot5\right)\\ =3^{24}\cdot45⋮45\left(đpcm\right)\)

c) Có: \(24^{54}\cdot54^{24}\cdot2^{10}\\ =\left(2^3\cdot3\right)^{54}\cdot\left(2\cdot3^3\right)^{24}\cdot2^{10}\\ =2^{162}\cdot3^{54}\cdot2^{24}\cdot3^{72}\cdot2^{10}\\ =2^{196}\cdot3^{126}\\ =2^7\cdot\left(2^{189}\cdot3^{126}\right)\\ =2^7\cdot\left[\left(2^3\right)^{63}\cdot\left(3^2\right)^{63}\right]\\ =2^7\left(8^{63}\cdot9^{63}\right)\\ =2^7\cdot72^{63}⋮72^{63}\left(đpcm\right)\)

a) ta có: 3 + 3² + 3³ + 3⁴ + ... + 3⁹⁹

= (3 + 3² + 3³) + (3⁴ + 3⁵ +36) + ... + (3⁹⁷ + 3⁹⁸ + 3⁹⁹)

= 3(1 + 3 + 3²) + 3⁴(1 + 3 + 3) + ... + 3⁹⁶(1 + 3 + 3)

= 3.13 + 3⁴.13 + ... + 3⁹⁶.13

= 13(3 + 3⁴ + ... + 3⁹⁶) ⋮ 13

vậy (3 + 3² + 3³ + 3⁴ + ... + 3⁹⁹) ⋮ 13

b) ta có: 81⁷ - 27⁹ - 9¹³

= (3⁴)⁷ - (3³)⁹ - (3²)¹³

= 3²⁸ - 3²⁷ - 3²⁶

= 3²⁶(3² - 3 - 1)

= 3²⁶ . 5 = 3²⁴ (9.5) = 3²⁴ . 45 ⋮ 45

Vậy (81⁷ - 27⁹ - 9¹³) ⋮ 45

c) ta có: 24⁵⁴.54²⁴.2¹⁰

= (2³.3)⁵⁴ . (2.3³)²⁴ . 2¹⁰

= 2¹⁶² . 3⁵⁴ . 2²⁴ . 3⁷² . 2¹⁰

= 2¹⁹⁶ . 3¹²⁶

= (2¹⁹³.3¹²⁴).(2³.3²)

= (2¹⁹³.3¹²⁴).72 ⋮ 72

vậy (24⁵⁴.54²⁴.2¹⁰) ⋮ 72

63:7=9

3:3=1

18:3=6

6:3=2

72:9=8

27:3=9

81:9-9

20:2=10

15:5=3

36:6=6

36:4=9

hok tốt

63:7=9

3:3=1

18:3=6

6:3=2

72:9=8

27:3=9

81:9=9

20:2=10

15:5=3

36:6=6

36:4=9

63 : 7 = 9

3 : 3 = 1

18 : 3 = 6

6 : 3 = 2

72 : 9 = 8

27 : 3 = 9

81 : 9 = 9

20 : 2 = 10

15 : 5 = 3

36 : 6 = 6

36 : 4 = 9

1: 243^5=(3^5)^5=3^25

3*27^8=3*3^24=3^25=243^5

3: 3^300=27^100

2^200=4^100

mà 27>4

nên 3^300>2^200

4: 15^2=3^2*5^2

81^3*125^3=3^12*5^9

=>15^2<81^3*125^3

6: 125^5=5^15

25^7=5^14

mà 15>14

nên 125^5>25^7

\(\dfrac{-54}{72}=\dfrac{-3}{4}\); \(\dfrac{42}{36}=\dfrac{7}{6}\);  \(\dfrac{2}{-3}=\dfrac{2}{-3}\)

\(\Rightarrow BCNN\left(4,6,-3\right)=12\)

Quy đồng

\(\dfrac{-3}{4}=\dfrac{-3.3}{4.3}=\dfrac{-9}{12}\)

\(\dfrac{7}{6}=\dfrac{7.2}{6.2}=\dfrac{14}{12}\)

\(\dfrac{2}{-3}=\dfrac{2.\left(-4\right)}{\left(-3\right).\left(-4\right)}=\dfrac{-8}{12}\)

9 + 18 + 27 + 36 + 45 + 54 + 63 + 72 + 90 = 414

kết quả là :

   414 

      đs...

1 x 9 = 9

2 x 9 = 18

3 x 9 = 27

4 x 9 = 36

5 x 9 = 45

6 x 9 = 54

7 x 9 = 63 

8 x 9 =72

9 x 9 = 81

10 x 9 = 90

Câu hỏi là : 9 + 18 + 27 + 36 + 45 + 54 + 63 + 72 + 81 +90 =414

a)

\(15+27+9+85+73\)

\(=\left(15+85\right)+\left(27+73\right)+39\)

\(=200+39\)

\(=329\)

b)

\(54.36+54.27+54.37\)

\(=54\left(36+27+37\right)\)

\(=54.100\)

\(=5400\)

c)

\(168-3^7:3^4+2013^0\)

\(=168-3^3+1\)

\(=168-27+1\)

\(=142\)

d)

\(3^4.15+81.26+27.59.3\)

\(=81.15+81.26+81.59\)

\(=81.\left(15+26+59\right)\)

\(=81.100\)

\(=8100\)

Tính giá trị của các biểu thức sau :

a.15 + 27 + 39 + 85 + 73

= ( 15 + 85 ) + ( 27 + 73 ) + 39

= 100 + 100 + 39

= 200 + 39

= 239

b. 54 .36 + 54 . 27 + 54 . 37

= 54 . ( 36 + 27 + 37 )

= 54 . 100

= 5400

c.168 - 3⁷ : 3⁴ + 2013⁰

= 168 - 3³ + 1

= 168 - 27 + 1

= 141 + 1

= 142

đ. 3⁴ . 15 + 81 . 26 + 27 . 59 . 3

= 3⁴ . 15 + 3⁴ . 26 + 3⁴ . 59

= 3⁴ . ( 15 + 26 + 59 )

= 81 . 100

= 8100

a.15 + 17 + 39 + 85 + 73

= ( 15 + 85 ) + ( 17 + 73 ) + 39

= 100 + 90 + 39

= 229

b. 54.36+54.27+54.37

= 54.(36+27+37)

= 54.100

=5400

c.168-3^7_:3⁴+2013⁰

⁼ 168-3^7-4+1

= 168-3³+1

= 168-27+1

= 142

d.3⁴.15+81.26+27.59.3

= 3⁴.15+3⁴.26+3³.59.3

= 3⁴.15+3⁴.26+3⁴.59

= 3⁴.(15+26+59)

= 3⁴.100

= 81.100

= 8100

a. =(1+10)×10 :2

=11×10:2

=110:2

=55

b. Số các số hạng là =(90-9):9+1= 10

Tổng = (9+90)×10:2=495

cần gấp bài 1 và bài 3, bài 2 k có cx đc 

9 x 2 = 18              9 x 3 = 27                  9 x 4 = 36                      9 x 5 = 45

18 : 9 = 2               27 : 9 = 3                  36 : 9 = 4                        45 : 9 = 5

9 x 6 = 54              9 x 7 = 63                  9 x 8 = 72                       9 x 9 = 81

54 : 9 = 6               63 : 9 = 7                   72 : 9 = 8                       81 : 9 = 9