-190

k nha

\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)

\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)

\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)

\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)

\(=0,2-\dfrac{2}{3}\)

\(=-\dfrac{7}{15}\)

\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)

\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)

\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)

\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)

\(=\dfrac{13}{26}\)

\(=\dfrac{1}{2}\)

#\(Toru\)

\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)

95 - (129 - 74) : 5 + 2022⁰

= 95 - 55 : 5 + 1

= 95 - 11 + 1

= 95 - 10

= 85

-------

(-67) + 125 + (-33) + 75

= (125 + 75) - (67 + 33)

= 200 - 100

= 100

--------

86.(-108) + 86.9 - 86

= 86.(-108 + 9 - 1)

= 86.(-100)

= 8600

Bài 1: thực hiện phép tính

a) (-95)*(1-305)-305*95=-95

b) (-18-9)*(-18+9)=243

c) 37*(-9)+37*(-1)=-370

d) 135*15+(-135)*85=-9450

e) (-2)⁴*|-5|=80

f) (-5)²*2⁵ =800

g) (-1)*3²=-9

Bài 2:Viết các tích sau thành dạng lũy thừa của 1 số

a) (-8)*(-3)²*(+125)=(-20.8....)^3

b)27*(-2)³*(-7)*(+49)=42^3

bạn ơi phải ghi rõ ràng

Nguyen Le Minh Ngoc              E thông cảm !

Cj đg ôn thi nên k có t/g lm đầy đủ

Sr e nhoa !

Chúc e hk tốt !

a, 120
b,10
c,-100
d,0

a) (-125) + 100 + 80 + 125 + 20

= [(-125) + 125] + (80 + 20) + 100

= 0 + 100 + 100

= 200

b) 27 + 55 + (-17) + (-55)

= [27 + (-17)] + [55 + (-55)]

= (27 - 17) + 0

= 10

c) (-92) + (-251) + (-8) + 251

= [(-251) + 251] + [(-92) + (-8)]

= 0 - 100

= -100

d) (-31) + (-95) + 131 + (-5)

= [(-31) + 131) + [(-95) + (-5)]

= 100 + (-100)

= 0 

Hok tốt

a) -125 + 100 + 80 + 125 + 20

= ( -125 + 125 ) + ( 80 + 20 ) + 100

= 0 + 100 + 100

= 200

b) 27 + 55 + (-17) + (-55)

= [ 27 + (-17) ] + [ 55 +(-55) ]

= 10 + 0 

= 10

c) -92 + (-251) + (-8) + 251

= [ -92 + (-8) ] + ( -251 + 251 )

= -100 + 0 

= -100

d) -31 + (-95) + 131 + (-5)

= ( -31 + 131 ) + [ -95 + (-5) ]

= 100 + (-100) = 0

Bài 1: 

\(101\cdot125+101\cdot25-101\cdot50\)

\(=101\cdot\left(125+25-50\right)\)

\(=101\cdot100\)

\(=10100\)

Bài 2: 

\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)

\(=76\cdot115+24\cdot115\)

\(=115\cdot\left(76+24\right)\)

\(=115\cdot100\)

\(=11500\)

5:

a: =>15x=165

=>x=11

b: =>x(x+1)/2=55

=>x^2+x=110

=>x=10

4: =>7x=56

=>x=8

Bài 1:

101•125+101•25+101•50

= 101•(125+25-50)

=101•100

=10100

Bài 2:

76•115+56•24+59•24

= 76•115+24•(56+59)

= 76•115+24•115

= 115•(76+24)

= 115•100

= 11500

hdsghj

Bài 1 :

a) \(...=5^5:5^4=5\)

b) \(...=7^8:7^9=\dfrac{1}{7}\)

c) \(...=2^{15}:\left(2^6.2^5\right)=2^{15}:2^{11}=2^4=16\)

d) \(...=3^{28}:3^{26}=3^2=9\)

Bài 2 :

a) \(...=3^2.3^3:3^4=3^5:3^4=3\)

b) \(...=10^9-10^9=0\)

c) \(...=5^{10}.5^{30}:5^{12}=5^{40}:5^{12}=5^{28}\)

d) \(...=5^{12}:5^9=5^3=125\)