a) \(10-2\left(4-3x\right)=-4\)

\(2\left(4-3x\right)=10-\left(-4\right)\)

\(2\left(4-3x\right)=14\)

\(4-3x=\dfrac{14}{2}\)

\(4-3x=7\)

\(3x=4-7\)

\(3x=-3\)

\(x=-1\)

b) \(-12+3\left(-x+7\right)=-18\)

\(3\left(-x+7\right)=-18+12\)

\(3\left(-x+7\right)=-6\)

\(-x+7=-2\)

\(-x=-2-7\)

\(-x=-9\)

\(x=9\)

c) \(24:\left(3x-2\right)=-3\)

\(3x-2=24:\left(-3\right)\)

\(3x-2=-8\)

\(3x=-8+2\)

\(3x=-6\)

\(x=-2\)

d) \(-45:5\left(-3-2x\right)=3\)

\(5\left(-3-2x\right)=-45:3\)

\(5\left(-3-2x\right)=-15\)

\(-3-2x=-15:5\)

\(-3-2x=-3\)

\(-2x=-3+3\)

\(-2x=0\)

\(x=0\)

c) \(x^2-9=2\cdot\left(x+3\right)^2\)

\(\Leftrightarrow\left(x-3\right)\left(x+3\right)-2\left(x+3\right)^2=0\)

\(\Leftrightarrow\left(x+3\right)\left[x-3-2\left(x+3\right)\right]=0\)

\(\Leftrightarrow\left(x+3\right)\left(x-3-2x-6\right)=0\)

\(\Leftrightarrow\left(x+3\right)\left(-x-9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-9\end{matrix}\right.\)

b) \(x^3-3x^2+3x-1=0\)

\(\Leftrightarrow x^3-3\cdot x^2\cdot1+3\cdot x\cdot1^2-1^3=0\)

\(\Leftrightarrow\left(x-1\right)^3=0\)

\(\Leftrightarrow x-1=0\)

\(\Leftrightarrow x=1\)

d) \(x^2-8x+3x-24=0\)

\(\Leftrightarrow\left(x^2-8x\right)+\left(3x-24\right)=0\)

\(\Leftrightarrow x\left(x-8\right)+3\left(x-8\right)=0\)

\(\Leftrightarrow\left(x+3\right)\left(x-8\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-8=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=8\end{matrix}\right.\)

a) \(x^2-9=2\left(x+3\right)^2\)

\(\Leftrightarrow\left(x+3\right)\left(x-3\right)=2\left(x+3\right)^2\)

\(\Leftrightarrow2\left(x+3\right)^2-\left(x+3\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left(x+3\right)\left[2\left(x+3\right)-\left(x-3\right)\right]=0\)

\(\Leftrightarrow\left(x+3\right)\left[2x+6-x+3\right]=0\)

\(\Leftrightarrow\left(x+3\right)\left(x+9\right)=0\)

\(\)\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x+9=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-9\end{matrix}\right.\)

b) \(x^2-8x+3x-24=0\)

\(\Leftrightarrow\left(x-8\right)x+3\left(x-8\right)=0\)

\(\Leftrightarrow\left(x-8\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x+3=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-3\end{matrix}\right.\)

c) \(x^3-3x^2+3x-1=0\)

\(\Leftrightarrow\left(x-1\right)^3=0\)

\(\Leftrightarrow x-1=0\)

\(\Leftrightarrow x=1\)

dmm

a: \(\left(x+1\right)^3+\left(x-2\right)^3=2x^3+2\left(2x-1\right)^2-9\)

\(\Leftrightarrow x^3+3x^2+3x+1+x^3-6x^2+12x-8=2x^3+2\left(4x^2-4x+1\right)-9\)

\(\Leftrightarrow2x^3-3x^2+15x-7=2x^3+8x^2-8x-7\)

\(\Leftrightarrow-11x^2+23x=0\)

\(\Leftrightarrow x\left(-11x+23\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{23}{11}\end{matrix}\right.\)

\(\text{1/ (2x - 5) +17 =6}\\ 2x-5=6-17\\ 2x-5=-11\\ 2x=-11+5\\ x=-6:2\\ x=-3\)

\(2x-5=-11\Leftrightarrow x=-3\)

\(\text{2/ 10 - 2(4 - 3x) = - 4}\\ 2\left(4-3x\right)=10-\left(-4\right)\\ 2\left(4-3x\right)=14\\ 4-3x=14:2\\ 4-3x=7\\ 3x=4-7\\ x=-3:3\\ x=-1\)

12 - 2(4 - 3x) = -4

        2(4 - 3x) =-4+12

        2(4 - 3x) =  8

            4 - 3x  = 8 : 2

            4 - 3x  = 4

                 3x  = 4 - 4 

                 3x  =  0

                  x   = 0 : 3

                  x   =  0

Vậy x = 0

Đợi mk chút xíu tý mk giải nốt

 Tk cho mk nha

   Mk cảm ơn 

Trả lời :

a, = 0

Hok tốt nhé bạn ((:

b)24 : (3x - 2) = -3                                                                    

       3x - 2    = 24 : -3

       3x - 2    =   -8

       3x          =  -8 + 2

       3x          =     -6

         x          =    -6 : 3

        x           =       -2

Vậy x = -2

Tk cho mk nha

   Mk cảm ơn

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