\(=x^3-3x^2+6x^2-18x+8x-24\\ =\left(x-3\right)\left(x^2+6x+8\right)\\ =\left(x-3\right)\left(x^2+2x+4x+8\right)\\ =\left(x-3\right)\left(x+2\right)\left(x+4\right)\)

\(x^3+3x^2-10x-24=\left(x^3-3x^2\right)+\left(6x^2-18x\right)+\left(8x-24\right)=x^2\left(x-3\right)+6x\left(x-3\right)+8\left(x-3\right)=\left(x-3\right)\left(x^2+6x+8\right)=\left(x-3\right)\left[\left(x^2+2x\right)+\left(4x+8\right)\right]=\left(x-3\right)\left[x\left(x+2\right)+4\left(x+2\right)\right]=\left(x-3\right)\left(x+2\right)\left(x+4\right)\)

jup mình với mọi người

júp mink với ace ơi

a) \(-10x^2-17x+6\)

\(=-10x^2-20x+3x+6\)

\(=-10x\left(x+2\right)+3\left(x+2\right)\)

\(=\left(x+2\right)\left(3-10x\right)\)

b)\(x^2-10x+9\)

\(=x^2-x-9x+9\)

\(=x\left(x-1\right)-9\left(x-1\right)\)

\(=\left(x-1\right)\left(x-9\right)\)

c) \(x^2-10x+24\)

\(=x^2-4x-6x+24\)

\(=x\left(x-4\right)-6\left(x-4\right)\)

\(=\left(x-4\right)\left(x-6\right)\)

Đặt x²+10x+5=a.Ta có biểu thức là : a(a+8)+16=a²+8a+16=(a+4)²=(x²+10x+9)²

x³ - 7x² + 10x

=x³ - 2x² - 5x² + 10x

=(x³ -2x²) - (5x² - 10x)

= x²( x - 2) - 5x( x - 2)

= (x - 2) (x² - 5x)

Gõ trên máy tính nên hơi lâu 

Cảm ơn mình đê

-x²+10x-25=-(x²-10x+25)=-(x²-2.5+25)=-(x-5)²

`#3107.101107`

`x^2 - y^2 + 10x - 10y`

`= (x^2 - y^2) + (10x - 10y)`

`= (x - y)(x + y) + 10(x - y)`

`= (x + y + 10)(x - y)`

_____

Sử dụng HĐT:

`A^2 - B^2 = (A - B)(A + B).`

c1: x²-10x+24=(x²-2.x.5+5²)-1=(x-5)²-1=(x-5-1)(x-5+1)=(x-6)(x-4)

c2: x²-10x+24=x²-4x-6x+24=x(x-4)-6(x-4)=(x-6)(x-4)

c1 =x²-6x-4x+24

=x(x-6)-4(x-6)

=(x-4)(x-6)

c2 =x²-10x+25-1

=(x-5)²-1

=(x-5-1)(x-5+1)

=(x-6)(x-4)

\(x^2-xy-10x+10y\)

\(=x\left(x-y\right)-10\left(x-y\right)\)

\(=\left(x-y\right)\left(x-10\right)\)