- 62 + x = ( - 14 ) + 46 - x   

    x + x = ( - 14 ) + 46 + 62

        2x = 94

          x = 47

\(-62+x=\left(-14\right)+46-x\\ \Rightarrow x-62=32-x\\ \Rightarrow x-62-32+x=0\\ \Rightarrow2x-94=0\\ \Rightarrow2x=94\\ \Rightarrow x=47\\ b,5^{x+2}-5^x=10^2.6\\ \Rightarrow25.5^x-5^x=100.6\\ \Rightarrow24.5^x=600\\ \Rightarrow5^x=25\\ \Rightarrow5^x=5^2\\ \Rightarrow x=2\)

- 62 + x = ( - 14 ) + 46 - x   

    x + x = ( - 14 ) + 46 + 62

        2x = 94

          x = 47

bonus cho hỏi tại sao ở ngoài tên bn 1 đằng bên trang  cn lại 1 tên khác v chỉ mik với

`(x+2)+(x+5)+(x+8)+.....+(x+62)=714`

`=>(x+x+....+x)+(2+5+8+....+62)=714`

Từ 2 đến 62 có 21 số nên cũng có 21 x

`=>21x+((2+62).21)/2=714`

`=>21x+(64.21)/2=714`

`=>21x+32.21=714`

`=>21x+672=714`

`=>21x=714-672=42`

`=>x=42:21=2`

Vậy `x=2`

(x+2)+(x+5)+(x+8)+...+(x+62)=714  [ (62-2):3+1=21 hạng tử ]

= 21x X + (62-2):2 x 21= 714

<=> 21 x X + 630=714

<=>21x X= 714-630= 84

<=>X=84:21=4

Vậy: x=4

Các bạn trả lời sai hết rồi
Đáp án là 82

 ( x -4 ) x3 + 7 = 240

(x-4) x 3= 240 -7

(x-4) x 3 = 233

x-4= 233/3

x= 233/3 +4

x= 245/3

3 x ( X - 5 ) + 8 x X = 62

3 x X + 8 x X - 15 = 62

11 x X = 62 + 15

11 x X = 77

X=77:11

X=7

\(\left(x-4\right)\times3+7=240\)

\(\left(x-4\right)\times3=233\)

\(x-4=\dfrac{233}{3}\)

\(x=\dfrac{233}{3}+4\)

\(x=\dfrac{245}{3}\)

\(3\times\left(x-5\right)+8\times x=62\)

\(3\times x-15+8\times x=62\)

\(3\times x+8\times x=77\)

\(11\times x=77\)

\(x=\dfrac{77}{11}=7\)

kho

x+x+x+x+x=100⇔5x=100⇔x=100:5=20

\(x\) + \(x\) + \(x\) + \(x\) = 100

\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 =  100

\(x\) \(\times\) ( 1 + 1 + 1 + 1 + 1 ) = 100

\(x\) \(\times\) 5 = 100

\(x\)       = 100 : 5

\(x\)       = 20

\(x\) + \(x\) + \(x\) + \(x\) \(\times\) 5 = 200

\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 5 = 200

\(x\) \(\times\) ( 1 + 1 + 1 + 5) = 200

\(x\) \(\times\)  8 = 200

\(x\)         = 200 : 8

\(x\)         = 25

(\(x\) + 1) + (\(x\) + 4) + ( \(x\) + 7) + (\(x\) + 10) = 62

 \(x\) + 1 + \(x\) + 4 + \(x\)+ 7 + \(x\) + 10 = 62

( \(x\) + \(x\) + \(x\) + \(x\) ) + ( 1 + 4 + 7 + 10) = 62

( \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1) + 22 = 62

\(x\) \(\times\) ( 1 + 1 + 1 + 1)  + 22 = 62

\(x\)  \(\times\) 4 + 22 = 62

\(x\) \(\times\) 4 = 62 - 22

\(x\) \(\times\) 4 = 40

\(x\)         = 40 : 4

\(x\)         = 10

$x$ + $x$ + $x$ + $x$ = 100

$x$ $\times$ 1 + $x$ $\times$ 1 + $x$ $\times$1 + $x$ $\times$ 1 + $x$ $\times$ 1 =  100

$x$ $\times$ ( 1 + 1 + 1 + 1 + 1 ) = 100

$x$ $\times$ 5 = 100

$x$       = 100 : 5

$x$       = 20

$x$ + $x$ + $x$ + $x$ $\times$ 5 = 200

$x$ $\times$ 1 + $x$ $\times$ 1 + $x$ $\times$1 + $x$ $\times$ 5 = 200

$x$ $\times$ ( 1 + 1 + 1 + 5) = 200

$x$ $\times$  8 = 200

$x$         = 200 : 8

$x$         = 25

($x$ + 1) + ($x$ + 4) + ( $x$ + 7) + ($x$ + 10) = 62

 $x$ + 1 + $x$ + 4 + $x$+ 7 + $x$ + 10 = 62

( $x$ + $x$ + $x$ + $x$ ) + ( 1 + 4 + 7 + 10) = 62

( $x$ $\times$ 1 + $x$ $\times$ 1 + $x$ $\times$ 1 + $x$ $\times$ 1) + 22 = 62

$x$ $\times$ ( 1 + 1 + 1 + 1)  + 22 = 62

$x$  $\times$ 4 + 22 = 62

$x$ $\times$ 4 = 62 - 22

$x$ $\times$ 4 = 40

$x$         = 40 : 4

$x$         = 10

c: -62+x=-14+46

=>\(x-62=46-14=32\)

=>\(x=32+62=94\)

d: \(25+\left(x-5\right)=-123-\left(15-123\right)\)

=>\(x-5+25=-123-15+123\)

=>\(x+20=-15\)

=>\(x=-15-20=-35\)

`c) -62 + x = -14 + 46`

`-62 + x = 32`

`x = 32 - (-62)`

`x = 94`

Vậy `x = 94`

`d) 25 + ( x - 5 ) = -123 - ( 15 - 123 )`

`25 + ( x - 5 ) = -123 - 15 + 123`

`25 + ( x - 5 ) = - 15`

`x - 5 = -15 - 25`

`x - 5 = -40`

`x = -40 + 5`

`x = -35`

Vậy `x = -35`

a) x × 5 = 50 – 15

x × 5 = 35

x = 35 : 5

x = 7

b) x : 4 = 38 – 33

x : 4 = 5

x = 5 × 4

x = 20

c) x + 356 = 414 + 62

x + 356 = 476

x = 476 – 356

x = 120

d) x : 4 = 2 × 3

x : 4 = 6

x = 6 × 4

x = 24

\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)

12(x-1)=0

     (x-1)=0:12

      x-1=0

      x=0+1

      x= 1

Vậy x= 1

12 ( x - 1 ) = 0
       x - 1   = 0 : 12
       x - 1   = 0
=>   x        = 1

<=> \(\frac{1.2.3....31}{4.6.8....64}=2^n\Rightarrow\frac{1.2.3....30.31}{2\left(2.3.4.5...31\right).32}=2^n\Leftrightarrow\frac{1}{2.32}=2^n\Leftrightarrow\frac{1}{2^6}=2^n\)

=> 2^6.2^n = 1 

=> 2^ (n + 6 ) = 2^0

=> n+ 6  = 0 

=> n = - 6 

\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}....\frac{31}{64}=\frac{1.2.3....31}{4.6.8....64}=\frac{1.2.3....31}{2.3.2.4....2.32}=\frac{1.2.3....31}{2^{30}.\left(3.4....32\right)}=\frac{2}{2^{30}.32}=\frac{1}{2^{34}}=2^{-34}=2^n=>n=-34\)

2^n × 2³¹ = \(\dfrac{ }{ }\)2/4×4/6×6/8×...×62/64

2^n×2³¹=1/32=2^-5

2^n=2^-5 ÷ 2³¹=2^-36

=>n=-36