Chắc là \(+28^2\)

Ta có : \(A=\left(30-29\right)\left(30+29\right)+.....+\left(2-1\right)\left(2+1\right)\)

\(=30+29+28+...+2+1\)

\(=465< 600\)

Vậy ....

Sửa đề: \(A=30^2-29^2+28^2-27^2+...+2^2-1^2\)

\(=30+29+28+27+...+2+1\)

\(=465< 600\)

Vậy: A<600

Ta có 1² + 2² + 3² + …10² = 385

Suy ra ( 1² +2² + 3² +…+10² ) .3² = 385.3²

Do đó ta tính được A = 3² + 6² + 9² + …+30²  = 3465

A = \(\frac{6x\left(1+8+27\right)}{6x\left(12+96+324\right)}\)= \(\frac{36}{432}\)=\(\frac{1}{12}\)

A= 1*2*3=2*4(6+3*6*9/2*3*12+4*6*24+6*9*36 = 8843366808

đề vớ vẩn

1: \(A=2+2^2+2^3+2^4+...+2^{97}+2^{98}+2^{99}+2^{100}\)

\(=2\left(1+2+2^2+2^3\right)+...+2^{97}\left(1+2+2^2+2^3\right)\)

\(=15\left(2+2^5+...+2^{97}\right)\)

\(=30\left(1+2^4+...+2^{96}\right)⋮30\)

2:

\(B=3+3^2+3^3+...+3^{2022}\)

\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{2021}+3^{2022}\right)\)

\(=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{2020}\left(3+3^2\right)\)

\(=12\left(1+3^2+...+3^{2020}\right)⋮12\)

1)  35.18−5.7.28=−350

2)  45−5(12+9)=−60

1) 35.18-5.7.28

=630-5.7.28

= 630-980

=630+(-980)

=-(980-630)

=-350

1) 35 . 18 - 5 . 7 . 28
= 630 - 35 . 28
= 630 - 980
= -350

2) 45 - 5.(12+9)

= 45-5×21

= 45-105

=-60

3) 31. (-18) + 31. ( - 81) – 31

=31.(-18)+31+81+(-31)

=31.(-18)+[31+ -(31)]+81

câu 5 sai nha

1)  

2)  

1) 35.18-5.7.28

=630-5.7.28

= 630-980

=630+(-980)

=-(980-630)

=-350

3577/10 = 357,7

giải rõ hộ mk