Phân tích đa thức thành nhân tử
a) 4x2-81
b)3(x-y)+5x(y-x)
c) x(x+y)+6x+6y
d) 20x-5y
e)4x2y-8xy2+10x2y2
g) 4xy+8xyz
Bài 1: Phân tích thành nhân tử.
a) 20x – 5y e) 4x2y – 8xy2 + 10x2y2
b) 5x(x – 1) – 3x(x – 1) g) 20x2y – 12x3
c) x(x + y) – 6x – 6y h) 8x4 + 12x2y4 – 16x3y4
d) 6x3 – 9x2 k) 4xy2 + 8xyz
a) 20x - 5y
= 5(4x - y)
b) 5x(x - 1)- 3x(x - 1)
= 2x(x - 1)
c) x(x + y) - 6x - 6y
= x(x + y) - (6x + 6y)
= x(x + y) - 6(x + y)
= (x + y)(x - 6)
d) 6x³ - 9x²
= 3x²(2x - 3)
e) 4x²y - 8xy² + 10x²y²
= 2xy(2x - 4y + 5xy)
g) 20x²y - 12x³
= 4x²(5y - 3x)
h) 8x⁴ + 12x²y⁴ - 16x³y⁴
= 4x²(2x² + 3y⁴ - 4xy⁴)
k) 4xy² + 8xyz
= 4xy(y + 2z)
bài 1 :
a) 20x - 5y b) 5x ( x - 1 ) - 3x ( x - 1 )
c) x ( x + y ) - 6x - 6y d) 6x3 - 9x2 e) 4x2y - 8xy2 + 10x2y2
g) 20x2y - 12x3 h) 8x4+ 12x2y4- 16x3y4 k) 4xy2 + 8xyz
l) 3x(x + 1) - 5y( x + 1 ) m) 4x2 - 1 o) 9 - ( x - y )2
p) x3 + 27 n) ( x-y )2 - 4 r)x4 + 2x2 + 1
s) 4x2 - 12xy + 9y2 t) x2 - x - y2 - y u) x2 - 2xy + y2 - z2
v) x3 - x + y3 - y
GIẢI HỘ TUI VỚI Ạ
a) 20x-5y=5(4x-y)
b) 5x(x-1)-3x(x-1)=(5x-3x)(x-1)=2x(x-1)
c) x(x+y)-6x-6y=x(x+y)-(6x+6y)=x(x+y)-6(x+y)=(x-6)(x+y)
d) 6x3-9x2=3x2(2x-3)
e) 4x2y - 8xy2 + 10x2y2=2xy(2x-4y+5xy)
g) 20x2y-12x3=4x2(5y-3x)
h) 8x4+ 12x2y4- 16x3y4 = 4x2(2x2+3y4-4xy4)
k) 4xy2 + 8xyz=4xy(y+2z)
l) 3x(x + 1) - 5y( x + 1 )=(x+1)(3x-5y)
m) 4x2-1=(2x-1)(2x+1)
o) 9-(x-y)2=(3-x+y)(3+x-y)
p) x3+27=(x+3)(x2+3x+9)
n) (x-y)2-4=(x-y-2)(x-y+2)
r) x4 + 2x2 + 1=(x4+x2)+(x2+1)=x2(x2+1)+(x2+1)=(x2+1)2
s) 4x2 - 12xy + 9y2 = (2x-3y)2
t) x2 - x - y2 - y =(x2-y2)-(x+y)=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)
v) x3 - x + y3 - y = (x3+y3)-(x+y)=(x+y)(x2-xy+y2)-(x+y)=(x+y)(x2-xy+y2-1)
a: \(20x-5y=5\left(4x-y\right)\)
b: \(5x\left(x-1\right)-3x\left(x-1\right)=2x\left(x-1\right)\)
c: \(x\left(x+y\right)-6x-6y=\left(x+y\right)\left(x-6\right)\)
d: \(6x^3-9x^2=3x^2\left(x-3\right)\)
e: \(4x^2y-8xy^2+10x^2y^2=2xy\left(2x-4y+5xy\right)\)
Bài 1: Phân tích các đa thức sau thành nhân tử
a. 1 - 4x2
b. 8 - 27x3
c. 27 + 27x + 9x 2 + x3
d. 2x3 + 4x2 + 2x
e. x2 - 5x - y2 + 5y
f. x2 - 6x + 9 - y2
g. 10x (x - y) - 6y(y - x)
h. x2 - 4x - 5
i. x4 - y4
Bài 2: Tìm x, biết
a. 5(x - 2) = x - 2
b. 3(x - 5) = 5 - x
c. (x +2)2 - (x+ 2) (x - 2) = 0
Bài 3: Tìm giá trị nhỏ nhất của biểu thức
a. A = x2 - 6x + 11
b. B = 4x2 - 20x + 101
c. C = -x2 - 4xy + 5y2 + 10x - 22y + 28
a.
\(1-4x^2=\left(1-2x\right)\left(1+2x\right)\)
b.
\(8-27x^3=\left(2\right)^3-\left(3x\right)^3=\left(2-3x\right)\left(4+6x+9x^2\right)\)
c.
\(27+27x+9x^2+x^3=x^3+3.x^2.3+3.3^2.x+3^3\)
\(=\left(x+3\right)^3\)
d.
\(2x^3+4x^2+2x=2x\left(x^2+2x+1\right)=2x\left(x+1\right)^2\)
e.
\(x^2-y^2-5x+5y=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-5\right)\)
f.
\(x^2-6x+9-y^2=\left(x-3\right)^2-y^2=\left(x-3-y\right)\left(x-3+y\right)\)
g. 10x(x-y)-6y(y-x)
=10x(x-y)+6y(x-y)
=(x-y)(10x+6y)
h.x2-4x-5
=(x-5)(x+1)
i.x4-y4 = (x2-y2)(x2+y2)
B2.
a.5(x-2)=x-2
⇔5(x-2)-(x-2)=0
⇔4(x-2)=0
⇔x=2
b.3(x-5)=5-x
⇔3(x-5)+(x-5)=0
⇔4(x-5)=0
⇔x=5
c.(x+2)2-(x+2)(x-2)=0
⇔(x+2)[(x+2)-(x-2)]=0
⇔4(x+2)=0
⇔x=-2
1A. Phân tích các đa thức sau thành nhân tử:
a) x3+2x; b) 3x - 6y;
c) 5(x + 3y)- 15x(x + 3y); d) 3(x-y)- 5x(y-x).
1B. Phân tích các đa thức sau thành nhân tử:
a) 4x2 - 6x; b) x3y - 2x2y2 + 5xy;
c) 2x2(x +1) + 4x(x +1); d) 2 x(y - 1) - 2
y(1 - y).
5 5
2A. Phân tích các đa thức sau thành nhân tử: a) 2(x -1)3 - 5(x -1)2 - (x - 1);
b) x(y - x)3 - y(x - y)2 + xy(x - y);
c) xy(x + y)- 2x - 2y;
d) x(x + y)2 - y(x + y)2 + y2 (x - y).
2B. Phân tích đa thức thành nhân tử: a) 4(2-x)2 + xy - 2y;
b) x(x- y)3 - y(y - x)2 - y2(x - y);
c) x2y-xy2 - 3x + 3y;
d) x(x + y)2 - y(x + y) 2 + xy - x 2 .
1A:
a: \(x^3+2x=x\left(x^2+2\right)\)
b: \(3x-6y=3\left(x-2y\right)\)
c: \(5\left(x+3y\right)-15x\left(x+3y\right)\)
\(=5\left(x+3y\right)\left(1-3x\right)\)
d: \(3\left(x-y\right)-5x\left(y-x\right)\)
\(=3\left(x-y\right)+5x\left(x-y\right)\)
\(=\left(x-y\right)\left(5x+3\right)\)
1A. a. x(x2+2)
b. 3(x-2y)
c. 5(x+3y)(1-3x)
d. (x-y) (3-5x)
1B. a. 2x(2x-3)
b.xy(x2-2xy+5)
c. 2x(x+1)(x+2)
d. 2x(y-1)+2y(y-1)=2(y-1)(x-y)
1B:
a: \(4x^2-6x=2x\left(2x-3\right)\)
b: \(x^3y-2x^2y^2+5xy\)
\(=xy\left(x^2-2xy+5\right)\)
Phân tích đa thức thành nhân tử:
a) x^2+10x+25-y^2
b) 5x^3-7x^2+10x-14
c) -5y^2+30y-45
e) 4xy^2-8xyz+4xz^2
f) x^2+7x+10
k) 2x^7+6x^6+6x^5-2x^4
a)\(x^2+10x+25-y^2\)
\(=\left(x+5\right)^2-y^2\)
\(=\left(x+5+y\right)\left(x+5-y\right)\)
b)\(5x^3-7x^2+10x-14\)
\(=x^2\left(5x-7\right)+2\left(5x-7\right)\)
\(=\left(x^2+2\right)\left(5x-7\right)\)
c)\(-5y^2+30y-45\)
\(=-5\left(y^2-6y+9\right)\)
\(=-5\left(y-3\right)^2\)
e)\(4xy^2-8xyz+4xz^2\)
\(=4x\left(y^2-2yz+z^2\right)\)
\(=4x\left(y-z\right)^2\)
f)\(x^2+7x+10\)
\(=x^2+5x+2x+10\)
\(=x\left(x+5\right)+2\left(x+5\right)\)
\(=\left(x+2\right)\left(x+5\right)\)
k)\(2x^7+6x^6+6x^5-2x^4\)
\(=2x^4\left(x^3+3x^2+3x-1\right)\)
a)\(x^2+10x+25-y^2\)
\(=\left(x+5\right)^2-y^2\)
\(=\left(x+5-y\right)\left(x+5+y\right)\)
b)\(5x^3-7x^2+10x-14\)
\(=x^2\left(5x-7\right)+2\left(5x-7\right)\)
\(=\left(5x-7\right)\left(x^2+2\right)\)
c)\(-5y^2+30y-45\)
\(=-5\left(y^2-6y+9\right)\)
\(=-5\left(y-3\right)^2\)
e)\(4xy^2-8xyz+4xz^2\)
\(=4x\left(y^2-2yz+z^2\right)\)
\(=4x\left(y-z\right)^2\)
f)\(x^2+7x+10\)
\(=x^2+5x+2x+10\)
\(=x\left(x+5\right)+2\left(x+5\right)\)
k)\(2x^7+6x^6+6x^5-2x^4\)
\(=2x^4\left(x^3+3x^2+3x-1\right)\)
\(=\left(x+2\right)\left(x+5\right)\)
Phân tích các đa thức sau thành nhân tử:
a) 2xy + 3z + 6y + xz; b) a 4 - 9 a 3 + a 2 - 9a;
c) 3 x 2 + 5y - 3xy + (-5x); d) x 2 - (a + b)x + ab;
e) 4 x 2 - 4xy + y 2 - 9 t 2 ; g) x 3 – 3 x 2 y + 3x y 2 – y 3 – z 3
h) x2 - y2 + 8x + 6y + 7.
a) Cách 1.
Ta có 2xy + 3z + 6y + xz = (2xy + xz) + (3z + 6y)
= x(2 y + z)+3(z + 2 y) = (z + 2y)(x + 3).
Cách 2.
Ta có 2xy + 3z + 6y + xz = (2x1/ + 6y) + (3z + xz)
= 2y(x + 3) + z(3 + x) = (z + 2y)(x + 3).
b) Biến đổi được a 4 - 9 rt 3 + a 2 -9a = (a- 9)a( a 2 +1).
c) Biến đổi được 3 x 2 + 5y - 3xy + (-5x) = (x - y)(3x - 5).
d) Biến đổi được x 2 - (a + b)x + ab = (x- a)(x - b).
e) Ta có 4 x 2 - 4xy + y 2 – 9 t 2 = ( 2 x - y ) 2 - ( 3 t ) 2
= (2x - y - 3t )(2x - y + 31).
g) Ta có x 3 - 3 x 2 y + 3 xy 2 - y 3 - z 3
= ( x - y ) 3 - z 3 = (x - y - z)( x 2 + y 2 + z 2 - 2xy + xz - yz).
h) Ta có x 2 - y 2 + 8x + 6y+ 7 = ( x 2 +8x + 16) - ( y 2 - 6y+ 9)
= ( x + 4 ) 2 - ( y - 3 ) 2 =(x-y + 7)(x + y + l).
phân tích đa thức thành nhân tử
a) (3x-6y) x+y (x-2y)
b) 3(x – y) – 5x(y – x)
b)2/5x(y-1)+2/5y(1-y)
d)x(x – 1) – y(1 – x)
a, \(\left(3x-6y\right)x+y\left(x-2y\right)=\left(3x+y\right)\left(x-2y\right)\)
b, \(3\left(x-y\right)-5x\left(y-x\right)=\left(3+5x\right)\left(x-y\right)\)
c, \(\dfrac{2}{5}x\left(y-1\right)+\dfrac{2}{5}y\left(1-y\right)=\left(\dfrac{2}{5}x-\dfrac{2}{5}y\right)\left(y-1\right)=\dfrac{2}{5}\left(x-y\right)\left(y-1\right)\)
d, \(x\left(x-1\right)-y\left(1-x\right)=\left(x+y\right)\left(x-1\right)\)
Phân tích mỗi đa thức sau thành nhân tử
a)x^3-2x^2y+xy^2+xy
b)x^3+4x^2y+4xy^2-9x
c)x^3-y^3+x-y
d)4x^2-4xy+2x-y+y^2
e)9x^2-3x+2y-4y^2
f)3x^2-6xy+3y^2-5x+5y
a) Xem lại đề
b) x³ - 4x²y + 4xy² - 9x
= x(x² - 4xy + 4y² - 9)
= x[(x² - 4xy + 4y² - 3²]
= x[(x - 2y)² - 3²]
= x(x - 2y - 3)(x - 2y + 3)
c) x³ - y³ + x - y
= (x³ - y³) + (x - y)
= (x - y)(x² + xy + y²) + (x - y)
= (x - y)(x² + xy + y² + 1)
d) 4x² - 4xy + 2x - y + y²
= (4x² - 4xy + y²) + (2x - y)
= (2x - y)² + (2x - y)
= (2x - y)(2x - y + 1)
e) 9x² - 3x + 2y - 4y²
= (9x² - 4y²) - (3x - 2y)
= (3x - 2y)(3x + 2y) - (3x - 2y)
= (3x - 2y)(3x + 2y - 1)
f) 3x² - 6xy + 3y² - 5x + 5y
= (3x² - 6xy + 3y²) - (5x - 5y)
= 3(x² - 2xy + y²) - 5(x - y)
= 3(x - y)² - 5(x - y)
= (x - y)[(3(x - y) - 5]
= (x - y)(3x - 3y - 5)