nhớ giải bằng cách hợp lí ra nhé

Lời giải:

$A=(1-4)+(7-10)+(13-16)+....+(97-100)+103$

$=\underbrace{(-3)+(-3)+(-3)+...+(-3)}_{17}+103$

$=(-3).17+103=52$

a, -10

b, 20

c, -20

d, -30

a) 10 – 12 – 8 = 10 – (12 + 8) = 10  - 20 = - 10

b) 4 – (- 15) – 5 + 6 = (4 + 6) – [(-15) + 5)] = 10 – (- 10) = 10 + 10 = 20

c) 2 – 12 – 4 – 6 = (2 – 12) - (4 + 6) = -10 + (- 10) = - 20

d) – 45 – 5 – (- 12) + 8 = - (45 + 5) + (12 + 8) = (- 50) + 20 = - 30

a) 10-12-8=2-12=-10

b) 4-(-15)-5+6=4+15-5+6=10+10=20

c) 2-12-4-6=-10-10=-20

d) -45-5-(-12)+8=-50+12+8=-50+20=-30

a) (-1) + 2 + (-3) + 4 + .... + (-2009) + 2010

= (-1 + 2) + (-3 + 4) + ..... + (-2009 + 2010)

= -1 + (-1) + (-1) + .... + (-1) 

= -1 . 1005 = -1005

b) 1 + (-2) + (-3) + 4 + 5 + (-6) + (-7) + 8 + ... + 2005 + (-2006) + (-2007) + 2008

= [1 + (-2) + (-3) + 4] + [5 + (-6) + (-7) + 8 ] + ..... + [2005 + (-2006) + (-2007) + 2008]

= 0 + 0 + ...... + 0 = 0

ghe

a) Ta có: \(\left(-1\right)+2+\left(-3\right)+4+...+\left(-2009\right)+2010\)

\(=1+1+...+1\)

=1005

b) Ta có: \(1+\left(-2\right)+\left(-3\right)+4+5+\left(-6\right)+\left(-7\right)+8+...+2005+\left(-2006\right)+\left(-2007\right)+2008\)

\(=\left(1-2-3+4\right)+\left(5-6-7+8\right)+...+\left(2005-2006-2007+2008\right)\)

=0

a) (-2 019) + (-550) + (-451)  = [(-2 019) + (-451)] + (-550) = (-2 470) + (-550) = -(2 470 + 550) = -3 020

b) (-2) + 5 + (-6) + 9 = [(-2) + 5 ]+[ (-6) + 9] = 3 + 3 = 6

a: \(=\dfrac{3}{7}+\dfrac{7}{8}+\dfrac{4}{7}-\dfrac{15}{8}=1-1=0\)

b: \(=\dfrac{1}{2}+\dfrac{4}{5}+\dfrac{3}{8}-\dfrac{7}{40}+\dfrac{1}{2}\)

\(=1+\dfrac{32+15-7}{40}=1+1=2\)

1: \(\dfrac{1}{2}+\dfrac{9}{10}+\dfrac{5}{6}-\dfrac{11}{14}-\dfrac{1}{3}+\dfrac{-4}{35}\)

\(=\left(\dfrac{1}{2}+\dfrac{5}{6}-\dfrac{1}{3}\right)+\dfrac{9}{10}-\left(\dfrac{11}{14}+\dfrac{4}{35}\right)\)

\(=\dfrac{3+5-2}{6}+\dfrac{9}{10}-\dfrac{55+8}{70}\)

\(=1+\dfrac{9}{10}-\dfrac{9}{10}\)

=1

a)\(\frac{7}{3}.\left( { - 2,5} \right).\frac{6}{7} = \frac{7}{3}.\frac{6}{7}.\left( { - 2,5} \right) = 2.\left( { - 2,5} \right) =  - 5\)

b)

\(\begin{array}{l}0,8.\frac{{ - 2}}{9} - \frac{4}{5}.\frac{7}{9} - 0,2\\ = \frac{4}{5}.\frac{{ - 2}}{9} - \frac{4}{5}.\frac{7}{9}-\frac{2}{10}\\ = \frac{4}{5}.\left( {\frac{{ - 2}}{9} - \frac{7}{9}} \right) -\frac{1}{5}\\ = \frac{4}{5}.\left( { - 1} \right)-\frac{1}{5} \\= \frac{{ - 4}}{5}-\frac{1}{5}\\=\frac{-5}{5}\\=-1.\end{array}\)

a) 14,7 + (-8,4) + (-4,7) = (14,7 - 4,7) + (-8,4)

= 10 - 8,4 = 1,6

b) (-4,2).5,1 + 5,1.(-5,8) = 5,1. (- 4,2 - 5,8)

= 5,1. (-10) = -51

c) (-0,4: 0,04 + 10) . (1,2.20 + 12.8)

= (-10 + 10). (1,2.20 + 12.8)

= 0. (1,2.20 + 12.8) = 0.