= (56,46-25) : ( 23 : 23)

= 31,46 : 1

= 31,46

\(\left(2^{17}+7^2\right).\left(9^{15}-3^{15}\right).\left(2^4-4^2\right)\)

\(=\left(2^{17}+7^2\right).\left(9^{15}-3^{15}\right).\left(16-16\right)\)

\(=\left(2^{17}+7^2\right).\left(9^{15}-3^{15}\right).0\)

\(=0\)

-------------------------------------------------

\(\left(7^{1997}-7^{1995}\right):\left(7^{1994}.7\right)\)

\(=\left[7^{1995}\left(7^2-1\right)\right]:7^{1995}\)

\(=7^{1995}.48:7^{1995}\)

\(=48\)

-------------------------------------------------

\(\left(1^2+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).\left(3^8-81^2\right)\)

\(=\left(1^2+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).\left(6561-6561\right)\)

\(=\left(1^2+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).0\)

\(=0\)

-------------------------------------------------

\(\left(2^8+8^3\right):\left(2^5.2^3\right)\)

\(=\left[2^8+\left(2^3\right)^3\right]:2^8\)

\(=\left(2^8+2^9\right):2^8\)

\(=2^8.\left(1+2\right):2^8\)

\(=2^8.3:2^8\)

\(=3\)

sos

\((2^{17}+17^{2}).(9^{15}-3^{15}).(2^{4}-4^{2})\)

\(=(2^{17}+17^{2}).(9^{15}-3^{15}).(16-16)\)

\(=(2^{17}+17^{2}).(9^{15}-3^{15}).0\)

\(=0\)

\((7^{1997}-7^{1995}):(7^{1994}.7)\)

\(=(7^{1997}-7^{1995}):7^{1995}\)

\(=7^{1997}:7^{1995}-7^{1995}:7^{1995}\)

\(=7^{2}-1=49-1=48\)

\(1^{2}+2^{3}+3^{4}+4^{5}).(1^{3}+2^{3}+3^{3}+4^{3}).(3^{8}-81^{2})\)

\(=(1^{2}+2^{3}+3^{4}+4^{5}).(1^{3}+2^{3}+3^{3}+4^{3}).(6561-6561)\)

\(=(1^{2}+2^{3}+3^{4}+4^{5}).(1^{3}+2^{3}+3^{3}+4^{3}).0\)

\(=0\)

\((2^{8}+8^{3}):(2^{5}.2^{3})\)

\(=[2^{8}+(2^{3})^{3}]:2^{8}\)

\(=(2^{8}+2^{9}):2^{8}\)

\(=2^{8}:2^{8}+2^{9}:2^{8}\)

\(=1+2=3\)

a: Ta có: \(\left(2^{17}+17^2\right)\cdot\left(9^{15}-3^{15}\right)\cdot\left(2^4-4^2\right)\)

\(=\left(2^{17}+17^2\right)\cdot\left(9^{15}-3^{15}\right)\cdot\left(16-16\right)\)

=0

b: Ta có: \(\dfrac{8^{2017}-8^{2015}}{8^{2104}\cdot8}\)

\(=\dfrac{8^{2015}\cdot\left(8^2-1\right)}{8^{2105}}\)

\(=\dfrac{1\cdot63}{8^{90}}\)+

c: Ta có: \(\left(1^3+2^3+3^4+4^5\right)\cdot\left(1^3+2^3+3^3+4^3\right)\cdot\left(3^8-81^2\right)\)

\(=\left(1^3+2^3+3^4+4^5\right)\cdot\left(1^3+2^3+3^3+4^3\right)\cdot\left(3^8-3^8\right)\)

=0

d: Ta có: \(\left(2^8+8^3\right):\left(2^5\cdot2^3\right)\)

\(=\dfrac{2^8+2^9}{2^8}\)

=3

\(a,A=\left(2^{17}+17^2\right)\left(9^{15}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right)\left(3^{30}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right).0.\left(2^4-32^2\right)\)

\(\Rightarrow A=0.\)

\(\Rightarrow B=\left(2^8.8^3\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=\left(2^8.2^9\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=2^{17}:2^8\)

\(\Rightarrow B=2^9\)

\(\Rightarrow B=512\)

\(c,C=64^4.16^5:4^{20}\)

\(\Rightarrow C=2^{24}.2^{20}:2^{40}\)

\(\Rightarrow C=2^4\)

\(\Rightarrow C=16\)

a: \(A=\left(2^{17}+17^2\right)\cdot\left(2^4-32^2\right)\cdot\left(3^{30}-3^{30}\right)=0\)

b: \(B=\dfrac{2^8\cdot2^9}{2^5\cdot2^3}=2^9\)

c: \(C=2^{24}\cdot2^{20}:2^{40}=2^4=16\)

1) 

3³ . 18 + 72 . 4² - 41 . 18

= 3³ . 18 + 18 . 4³ - 41 . 18

= 18 . ( 3³ + 4³ - 41 )

= 18 . 50

= 900

2) ( 56 . 46 - 25 . 23 ) : 23

= ( 112 . 23 - 25 . 23 ) : 23

= ( 112 - 25 ) . 23 : 23

= 87 . 23 : 23

= 87

3) ( 76 . 34 - 19 . 64 ) : ( 38 . 9 )

= ( 19 . 136 - 19 . 64 ) : ( 19 . 18 )

= 19 . ( 136 - 64 ) : ( 19 . 18 )

= 19 . 72 : 19 . 18

= 19 . 4

= 76

4) ( 5 . 4¹¹ - 3 . 16⁵ ) : 4¹⁰

= ( 5 . 4¹¹ - 3 . 4¹⁰ ) : 4¹⁰

= ( 20 . 4¹⁰ - 3 . 4¹⁰ ) : 4¹⁰

= ( 20 - 3 ) . 4¹⁰ : 4¹⁰

= 17

Bai nay minh lam roi bang 17 do

24.47 - \(\frac{23}{24}\)+ 47 - 23

= 24.47 - 0.9583333333 + 47 - 23

= 23.51166667 + 47 - 23

= 70.51166667 - 23

= 47.51166667

22 + 23 + 24 +... + 27 + 28 = (22 + 28) + (23 + 27) + (24 + 26) + 25

= 50 + 50 + 50 + 25 = 175