Question

Tính hợp lý (nếu có thể)
a) A = (2¹⁷+17²).(9¹⁵ – 3³⁰ ).(2⁴ – 32²)  
b) B =(2⁸.8³) : (2⁵.2³) 
c) C = 64⁴.16⁵ : 4²⁰

Answer 1

\(a,A=\left(2^{17}+17^2\right)\left(9^{15}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right)\left(3^{30}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right).0.\left(2^4-32^2\right)\)

\(\Rightarrow A=0.\)

\(\Rightarrow B=\left(2^8.8^3\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=\left(2^8.2^9\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=2^{17}:2^8\)

\(\Rightarrow B=2^9\)

\(\Rightarrow B=512\)

\(c,C=64^4.16^5:4^{20}\)

\(\Rightarrow C=2^{24}.2^{20}:2^{40}\)

\(\Rightarrow C=2^4\)

\(\Rightarrow C=16\)

 

Answer 2

a: \(A=\left(2^{17}+17^2\right)\cdot\left(2^4-32^2\right)\cdot\left(3^{30}-3^{30}\right)=0\)

b: \(B=\dfrac{2^8\cdot2^9}{2^5\cdot2^3}=2^9\)

c: \(C=2^{24}\cdot2^{20}:2^{40}=2^4=16\)