a) \(\left(-48\right)+127+\left(-52\right)+73\)

\(=\left(-48-52\right)+\left(127+73\right)\)

\(=-100+200\)

\(=100\)

b) \(\left(-38\right)\cdot45+\left(-38\right)\cdot55\)

\(=\left(-38\right)\cdot\left(45+55\right)\)

\(=\left(-38\right)\cdot100\)

\(=-3800\)

c) \(\left(-125\right)+371+\left(-875\right)+629+150\)

\(=\left(-125-875\right)+\left(371+629\right)+150\)

\(=-1000+1000+150\)

\(=150\)

d) \(271+\left(-392\right)+729+\left(-608\right)+\left(-123\right)\)

\(=\left(271+729\right)+\left(-392-608\right)-123\)

\(=1000-1000-123\)

\(=-123\)

e) \(\left(-48\right)\cdot25+25\cdot\left(-52\right)\)

\(=25\cdot\left(-48-52\right)\)

\(=25\cdot-100\)

\(=-2500\)

f) \(47\cdot\left(-11\right)+47\)

\(=47\cdot\left(-11+1\right)\)

\(=47\cdot-10\)

\(=-470\)

g) \(56-7\cdot8+11\)

\(=56-56+11\)

\(=0+11\)

\(=11\)

h) \(-42+51+2+\left(-11\right)+40\)

\(=\left(-42+2\right)+\left(51-11\right)+40\)

\(=-40+40+40\)

\(=0+40\)

\(=40\)

a: =-48-52+127+73

=200-100

=100

b; \(=-38\left(45+55\right)=-38\cdot100=-3800\)

c: \(=-125-875+371+629+150\)

=-1000+1000+150

=150

d: =271+729-392-608-123

=1000-1000-123

=-123

e: =25(-48-52)

=25*(-100)

=-2500

f: =47(-11+1)

=47(-10)

=-470

g: =56-56+11

=11

h: =-42+2+51-11+40

=-40+40+40

=40

11 - 47 : x = 52 : x
=> 11 = 52 : x + 47 : x
=> 11 = (52 + 47) : x
=> 11 = 99 : x
=> x = 99 : 11
=> x = 9

a, 

= 51 - 2022 + 2022

= 51

b, = -2019 - 11 + 2019

    = -11

c, = 27 - 52 - 37 + 52

= -10

d, = 19 - 32 + 41 - 19 + 25 - 41

= -7

a)    (51 - 2022) + 2022

=51+(-2022+2022)

=51+0

=51

b)    (-2019) - (11 - 2019)

=(-2019)-11+2019

=(-2019+2019)-11

=0-11

=-11

c)    (27 - 52) - (37 - 52)

=27-52-37+52

=[27+(-37)]+(-52+52)

=-10+0

=-10

d) (19 - 32 + 41) - (19 - 25 + 41)

=19-32+41-19+25-41

=(19-19)+(-32-25)+(41-41)

=0+(-57)+0

=-57

\(3^2\times\left[\left(5^2-3\right)\div11\right]-2^4+2\times10^3\)

\(=9\times\left[\left(25-3\right)\div11\right]-16+2\times1000\)

\(=9\times\left(22\div11\right)-16+2000\)

\(=9\times2-16+2000\)

\(=18-16+2000\)

\(=2+2000\)

\(2002\)

\(\left(7x-11\right)^3=2^5.5^2+2.10^2\)

\(\Rightarrow\left(7x-11\right)^3=32.25+2.100\)

\(\Rightarrow\left(7x-11\right)^3=800+200\)

\(\Rightarrow\left(7x-11\right)^3=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

(7\(x\) - 11)³ = 2⁵.5² + 2.10²

(7\(x\) - 11)³ = 1000

(7\(x\) - 11)³ = 10³

7\(x\) - 11 = 10

7\(x\)        = 10 + 11

7\(x\)        = 21

   \(x\)       = 21:7

   \(x\)        = 3

\(\left(7x-11\right)^3=2^5.5^2+2.10^2\)

\(\left(7x-11\right)^3=2^5.5^2+2.\left(2.5\right)^2\)

\(\left(7x-11\right)^3=2^5.5^2+2.2^2.5^2\)

\(\left(7x-11\right)^3=2^5.5^2+2^3.5^2\)

\(\left(7x-11\right)^3=5^2\left(2^5+2^3\right)\)

\(\left(7x-11\right)^3=5^2\left(32+8\right)\)

\(\left(7x-11\right)^3=5^2.40\)

\(\left(7x-11\right)^3=25.40\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=10+11\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=21:7\)

\(\Rightarrow x=3\)

\(B=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+\frac{1}{18\cdot19\cdot20}\)

\(B=\frac{1}{2}\left(\frac{2}{1\cdot2\cdot3}+\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+\frac{2}{18\cdot19\cdot20}\right)\)

\(B=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{2\cdot3}+\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{18\cdot19}-\frac{1}{19\cdot20}\right)\)

\(B=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{19\cdot20}\right)\)

\(B=\frac{1}{2}\cdot\frac{189}{380}=\frac{189}{760}\)

\(C=\frac{52}{1\cdot6}+\frac{52}{6\cdot11}+\frac{52}{11\cdot16}+...+\frac{52}{31\cdot36}\)

\(C=\frac{52}{5}\left(\frac{5}{1\cdot6}+\frac{5}{6\cdot11}+\frac{5}{11\cdot16}+...+\frac{6}{31\cdot36}\right)\)

\(C=\frac{52}{5}\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{31}-\frac{1}{36}\right)\)

\(C=\frac{52}{5}\cdot\left(1-\frac{1}{36}\right)\)

\(C=\frac{91}{9}\)

vì mk bận hok nên chỉ ghi vắn tắt đc kq thui nhé !

\(=136\)nha m.n

thấy mk ủng hộ nha ! lâu rùi mk mới quay lại !

trung thu vui vẻ...

số đó là

136

ai k mình

mình k laijc ho

136 nhe tk nhe

\(\left(7x-11\right)^3=2^5\cdot5^2+200\cdot2023^0\\ \left(7x-11\right)^3=32\cdot25+200\cdot1\\ \left(7x-11\right)^3=1000\\ \left(7x-11\right)^3=10^3\\ 7x-11=10\\ 7x=21\\ x=\dfrac{21}{7}=3\)

Lời giải:

$(7x-11)^3=2^5.5^2+200.2023^0=32.25+200=1000=10^3$

$\Rightarrow 7x-11=10$

$\Rightarrow 7x=21$

$\Rightarrow x=3$