a: \(125^5:25^3=5^{15}:5^6=5^9\)

b: \(27^6:9^3=3^{18}:3^6=3^{12}\)

c: \(4^{20}:2^{15}=2^{40}:2^{15}=2^{45}\)

d: \(24^n:2^{2n}=24^n:4^n=6^n\)

e: \(64^4\cdot16^5:4^{20}=2^{24}\cdot2^{20}:2^{40}=2^4\)

\(a,4^8.2^{20}=\left(2^2\right)^8.2^{20}=2^{16}.2^{20}=2^{16+20}=2^{36}\\ b,9^{12}.27^5.81^4=\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4=3^{24}.3^{15}.3^{16}=3^{24+15+16}=3^{55}\\ d,25^{20}.125^4=\left(5^2\right)^{20}.\left(5^3\right)^4=5^{40}.5^{12}=5^{40+12}=5^{52}\\ d,x^7.x^4.x^3=x^{7+4+3}=x^{14}\)

a: 4*8*2^20=2^2*2^3*2^20=2^25

b: 9^12*27^5*81^4=3^24*3^15*3^16=3^55

c: 25^20*125^4=5^40*5^12=5^52

d: =x^(7+4+3)=x^14

a) 4.9.16=2.2.3.3.4.4=2.2.3.3.2.2.2.2=2⁶.3²

b)4.6.9.15.25=2.2.3.2.3.3.3.5.5.5=2³.3⁴.5³=10³.3⁴

a) \(4^9:4^4\)

\(=4^{9-4}\)

\(=4^5\)

b) \(17^8:17^5\)

\(=17^{8-5}\)

\(=17^3\)

c) \(2^{10}:8^2\)

\(=2^{10}:\left(2^3\right)^2\)

\(=2^{10-6}\)

\(=2^4\)

d) \(18^{10}:3^{10}\)

\(=\left(18:3\right)^{10}\)

\(=6^{10}\)

e) \(27^5:81^3\)

\(=\left(3^3\right)^5:\left(3^4\right)^3\)

\(=3^{15}:3^{12}\)

\(=3^{15-12}\)

\(=3^3\)

f) \(10^6:100\)

\(=10^6:10^2\)

\(=10^{6-2}\)

\(=10^4\)

g) \(5^9:25^3\)

\(=5^9:\left(5^2\right)^3\)

\(=5^9:5^6\)

\(=5^{9-6}\)

\(=5^3\)

h) \(4^{10}:64^3\)

\(=4^{10}:\left(4^3\right)^3\)

\(=4^{10-9}\)

\(=4\)

i) \(2^{25}:32^4:18^4:9^4\)

\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)

\(=2^5:9^8:2^4\)

\(=2:9^8\)

\(=\dfrac{2}{9^8}\)

a,4^9-4

b,17^8-5

c,2^10-5

d,6^10

e,81

f,

a: \(\dfrac{4^9}{4^4}=4^{9-4}=4^5\)

b: \(\dfrac{17^8}{17^5}=17^{8-5}=17^3\)

c: \(2^{10}:8^2=2^{10}:2^6=2^4\)

d: \(18^{10}:3^{10}=\left(\dfrac{18}{3}\right)^{10}=6^{10}\)

e: \(=\dfrac{3^{15}}{3^{12}}=3^3\)

f: \(=\dfrac{10^6}{10^2}=10^4\)

g: =5^9:5^6=5^3

h: \(=\dfrac{4^{10}}{\left(4^3\right)^3}=\dfrac{4^{10}}{4^9}=4\)

i: \(=2^{25}:2^{20}\cdot\dfrac{1}{18^4}\cdot\dfrac{1}{9^4}\)

\(=\dfrac{2^5}{9^8\cdot2^4}=\dfrac{2}{9^8}\)

a) \({3.3^3} = 3.(3.3.3)= 3.3.3.3={3^4}\)

b) \({2^2}{.2^4}=(2.2).(2.2.2.2) =2.2.2.2.2.2= {2^6}\)

Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)

a) \(\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)=\left(-5\right)^5\)

b)\(\left(-2\right)\left(-2\right)\left(-2\right)\left(-3\right)\left(-3\right)\left(+3\right)=\left(-2\right)^3\cdot\left(-3\right)^2\cdot3=\left(-2\right)^3\cdot3^3\)

c) \(\left(-7\right)\cdot7\cdot5\cdot\left(-5\right)\left(-5\right)=\left(-7^2\right)\cdot\left(-5\right)^3\)

d) \(\left(-8\right)\left(-3\right)3\cdot125=\left(-2^3\right)\cdot\left(-3^2\right)\cdot5^3\)

e) \(27\cdot\left(-2\right)3\left(-7\right)\cdot49=3^4\cdot\left(-2\right)\cdot\left(-7^3\right)\)