\(\frac{30}{13}\)× \(\frac{52}{29}\)×\(\frac{116}{240}\)= \(\frac{3×10×13×4×29×4}{13×29×2×3×4×10}\)( gạch số giống nhau đi )=\(\frac{4}{2}\)= 2

k giúp mik nha

a) A= 100 - 116 : 4

=100-29

=71

b) B= 100 - [ 116 - (13 - 5)²]

=100-[116-8²]

=100-(116-64)

=100-52

=48

c) C= |- 65| + (- 42) + |65|

= 65+(-42)+65

= 88

a) A = 100 - 116 : 4

A = 100 - 29

A = 71

Vậy A = 71

b) B = 100 - [ 116 - ( 13 - 5 )² ]

B = 100 - [ 116 - 8² ]

B = 100 - [ 116 - 64 ]

B = 100 - 52

B = 48

Vậy B = 48

c) C = | - 65 | + ( - 42 ) + | 65 |

C = 65 + ( - 42 ) + 65

C = ( 65 + 65 ) + ( - 42 )

C = 130 + ( - 42 )

C = 130 - 42

C = 88

Bài 1:

\(\dfrac{-13}{38}\) và \(\dfrac{29}{-88}\) 

\(\dfrac{-13}{38}=\dfrac{-13.29}{38.29}=\dfrac{-377}{1102}\) 

\(\dfrac{29}{-88}=\dfrac{-29}{88}=\dfrac{-29.13}{88.13}=\dfrac{-377}{1144}\) 

Vì \(\dfrac{-377}{1102}< \dfrac{-377}{1144}\) nên \(\dfrac{-13}{38}< \dfrac{29}{-88}\) 

\(\dfrac{-18}{31}\) và \(\dfrac{-1818}{3131}\) 

\(\dfrac{-18}{31}\) 

\(\dfrac{-1818}{3131}=\dfrac{-1818:101}{3131:101}=\dfrac{-18}{31}\) 

Vì \(\dfrac{-18}{31}=\dfrac{-18}{31}\) nên \(\dfrac{-18}{31}=\dfrac{-1818}{3131}\)

Bài 2:

a) \(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4}{156}+\dfrac{-3}{156}=\dfrac{-4+-3}{156}=\dfrac{-7}{156}\) 

b) \(\dfrac{-6}{9}+\dfrac{-12}{16}=\dfrac{-2}{3}+\dfrac{-3}{4}=\dfrac{-8}{12}+\dfrac{-9}{12}=\dfrac{-17}{12}\)

\(13\cdot16+13\cdot\left(-116\right)+17\cdot\left(-100\right)\)

\(=13\left(16+-116\right)+17\cdot\left(-100\right)\)

\(=13\cdot\left(-100\right)+17\cdot\left(-100\right)\)

\(=\left(-100\right)\cdot\left(13+17\right)=30\cdot\left(-100\right)=-3000\)

  13.16+13.(-116)+17.(-100)

=13.(-116+16)+17.(-100)

=13.(-100)+17.(-100)

=(-100).(13+17)

=-100.30

=(-3000)

a. 10/13 + 9/16         
=160/208+117/208
=277/208
7/90 + 123/270
=7/90+41/90
=48/90
=8/15

b. 19/21 - 5/12                 
=76/84-35/84
=41/84
 90/100 - 25/40
=9/10-25/40
=36/40-25/40
=11/40

a. 10/13 + 9/16         
=160/208+117/208
=277/208
7/90 + 123/270
=7/90+41/90
=48/90
=8/15

b. 19/21 - 5/12                 
=76/84-35/84
=41/84
 90/100 - 25/40
=9/10-25/40
=36/40-25/40
=11/40

a) \(\dfrac{10}{13}+\dfrac{9}{16}\)                         \(\dfrac{7}{90}+\dfrac{123}{270}\)

= \(\dfrac{160}{208}+\dfrac{117}{208}\)                   = \(\dfrac{7}{90}+\dfrac{41}{90}\)

= \(\dfrac{277}{208}\)                              = \(\dfrac{8}{15}\)

b) \(\dfrac{19}{21}-\dfrac{5}{12}\)                       \(\dfrac{90}{100}-\dfrac{25}{40}\)

= \(\dfrac{76}{84}-\dfrac{35}{84}\)                      = \(\dfrac{9}{10}-\dfrac{25}{40}\)

= \(\dfrac{41}{84}\)                               = \(\dfrac{36}{40}-\dfrac{25}{40}\)

                                      = \(\dfrac{11}{40}\)

Hok tốt 

\(100-\left(116-\left(13-5^2\right)\right)=100-\left(116-\left(-12\right)\right)\)

\(=100-\left(116+12\right)=100-128=-28\)

100-[116-(13-5²)]

=100-[116-(13-25)]

=100-(116-13+25)

=100-(103+25)

=100-128

=-28

\(100-\left[116-\left(13-5\right)^2\right]\)

\(=100-\left(116-8^2\right)\)

\(=100-\left(116-64\right)\)

\(=100-52\)

\(=48\)

=100-(116-(9.9)

=100-(116-81)

=100-35=65

a) 2⁵ = 2.2.2.2.2 = 32

b) 3³ = 3.3.3 = 27

c) 5² = 5.5 =25

d) 10⁹ =10.10.10.10.10.10.10.10.10 = 1 000 000 000

a: =6^2-15*2

=36-30=6

b: =3*25+15*4-3

=72+60

=132

c: =25*2+5

=50+5

=55

d: =5+12=17

e: =7^2(15-5)=49*10=490

f: =4^3*125-125:25

=1000-5

=995

Câu 1: 

a:=17+5=22

b: =40-25=15