Question

100-[116-(13-5²)]

Answer 1

\(100-\left(116-\left(13-5^2\right)\right)=100-\left(116-\left(-12\right)\right)\)

\(=100-\left(116+12\right)=100-128=-28\)

Answer 2

100-[116-(13-5²)]

=100-[116-(13-25)]

=100-(116-13+25)

=100-(103+25)

=100-128

=-28