ta có\(\frac{237}{118}< \frac{354}{118}=3\)

\(3=\frac{993}{331}< \frac{994}{331}\)

vậy\(\frac{237}{118}< \frac{994}{331}\)

thấy hay thì tk mình nhe ^^

a ) Ta có :

\(1-\frac{41}{91}=\frac{50}{91}\) \(=\frac{500}{910}\)  ;  \(1-\frac{411}{911}=\frac{500}{911}\)

 Vì \(\frac{500}{910}>\frac{500}{911}\)nên \(\frac{41}{91}< \frac{411}{911}\)

b ) Ta có :

\(1-\frac{113}{115}=\frac{2}{115}\)   ;     \(1-\frac{93}{95}=\frac{2}{95}\)

Vì \(\frac{2}{115}< \frac{2}{95}\)nên \(\frac{113}{115}>\frac{93}{95}\).

c ) Quy đồng TS ta có :

\(\frac{13}{53}=\frac{143}{583}\) ;   \(\frac{11}{30}=\frac{143}{390}\)

Vì \(\frac{143}{583}< \frac{143}{390}\)nên   \(\frac{13}{53}< \frac{11}{30}\).

phải là Lục Cẩn Niên chứ !

995/559 > 749/594

473/548 < 956/596

659/495 > 485/594

a: \(2^{\dfrac{6}{3}}=2^2\)

b: \(2^{\dfrac{6}{3}}=2^2=4\)

\(\sqrt[3]{2^6}=\sqrt[3]{64}=4\)

=>\(2^{\dfrac{6}{3}}=\sqrt[3]{2^6}\)

a) $\frac{2}{3} = \frac{{2 \times 6}}{{3 \times 6}} = \frac{{12}}{{18}}$

Ta có $\frac{{12}}{{18}} > \frac{{11}}{{18}}$ nên $\frac{2}{3} > \frac{{11}}{{18}}$

b) $\frac{{36}}{{63}} = \frac{{36:9}}{{63:9}} = \frac{4}{7}$

Ta có $\frac{4}{7} < \frac{5}{7}$ nên $\frac{{36}}{{63}}$ < $\frac{5}{7}$

c)

$\frac{{55}}{{110}} = \frac{{55:55}}{{110:55}} = \frac{1}{2}$ ;  $\frac{4}{8} = \frac{1}{2}$

Vậy $\frac{{55}}{{110}}$ = $\frac{4}{8}$

Ta có:

\(\frac{{ - 7}}{{18}} = \frac{{ - 7.2}}{{18.2}} = \frac{{ - 14}}{{36}}\)

\(\frac{5}{{ - 12}} = \frac{{ - 5}}{{12}} = \frac{{ - 5.3}}{{12.3}} = \frac{{ - 15}}{{36}}\)

Vì \(\frac{{ - 14}}{{36}} > \frac{{ - 15}}{{36}}\) nên \(\frac{{ - 7}}{{18}} > \frac{5}{{ - 12}}\).